If the initial sample is 1.25 g, what mass of the original iridium‑192 remains after 65 days?mass remaining:0.675 g (this is correct, I just need answers to the next question)How many days would it take for one‑third of the sample to decay?time: Iridium-192 is one radioisotope used in brachytherapy, in which a radioactive source is placed inside a patient's body to treatcancer. Brachytherapy allows the use of a higher than normal dose to be placed near the tumor while lowering the risk of damageto healthy tissue. Iridium-192 is often used in the head or breast.Use the radioactive decay curve of iridium-192 to answer the three questions.Sample remaining (%)10090807060504030-2010.1020 3040 50607090 100 110 120 130 140 150 160 170 180 190Time (days)80

According to the question we have, Initial mass (original mass) of the sample= Mo = 1.25 g Time (t)…

Answered: If the initial sample is 1.25 g, what…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Question

If the initial sample is 1.25 g, what mass of the original iridium‑192 remains after 65 days?

mass remaining:
0.675 g (this is correct, I just need answers to the next question)
How many days would it take for one‑third of the sample to decay?
time:

Iridium-192 is one radioisotope used in brachytherapy, in which a radioactive source is placed inside a patient's body to treat
cancer. Brachytherapy allows the use of a higher than normal dose to be placed near the tumor while lowering the risk of damage
to healthy tissue. Iridium-192 is often used in the head or breast.
Use the radioactive decay curve of iridium-192 to answer the three questions.
Sample remaining (%)
100
90
80
70
60
50
40
30-
20
10.
10
20 30
40 50
60
70
90 100 110 120 130 140 150 160 170 180 190
Time (days)
80

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions