127 Cs -> "He + ? 55

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Complete the nuclear equation and identify the missing particle
### Nuclear Reaction Transcription

The image displays a nuclear reaction equation that needs to be completed by determining the missing product:

\[ \,^{127}_{55}\text{Cs} \rightarrow \,^{4}_{2}\text{He} + \,? \]

**Explanation:**
- **Reactant:**
  - The reactant here is Cesium-127 (\( \,^{127}_{55}\text{Cs} \)).
    - The superscript \(127\) indicates the mass number (sum of protons and neutrons).
    - The subscript \(55\) indicates the atomic number (number of protons).
  
- **Products:**
  - One of the products is Helium-4 (\( \,^{4}_{2}\text{He} \)).
    - The superscript \(4\) indicates the mass number (sum of protons and neutrons).
    - The subscript \(2\) indicates the atomic number (number of protons).
  - The other product is currently unknown and represented by a question mark (?).

### Completing the Nuclear Reaction

To balance this nuclear equation in terms of both mass number and atomic number, we must determine the missing product.

1. **Mass Number Balance:**
   - Total mass number on the left side (Reactants): \(127\)
   - Helium-4 (He) has a mass number of \(4\), so:
     \[ 127 = 4 + \text{Mass number of unknown product} \]
     \[ \text{Mass number of unknown product} = 127 - 4 = 123 \]

2. **Atomic Number Balance:**
   - Total atomic number on the left side (Reactants): \(55\)
   - Helium-4 (He) has an atomic number of \(2\), so:
     \[ 55 = 2 + \text{Atomic number of unknown product} \]
     \[ \text{Atomic number of unknown product} = 55 - 2 = 53 \]

Thus, the missing product will have a mass number of \(123\) and an atomic number of \(53\). The element with atomic number \(53\) is Iodine (symbol I).

### Completed Nuclear Reaction

The completed nuclear reaction is:

\[ \,^{127}_{55}\text{Cs} \rightarrow \,^{4}_{2}\text{
Transcribed Image Text:### Nuclear Reaction Transcription The image displays a nuclear reaction equation that needs to be completed by determining the missing product: \[ \,^{127}_{55}\text{Cs} \rightarrow \,^{4}_{2}\text{He} + \,? \] **Explanation:** - **Reactant:** - The reactant here is Cesium-127 (\( \,^{127}_{55}\text{Cs} \)). - The superscript \(127\) indicates the mass number (sum of protons and neutrons). - The subscript \(55\) indicates the atomic number (number of protons). - **Products:** - One of the products is Helium-4 (\( \,^{4}_{2}\text{He} \)). - The superscript \(4\) indicates the mass number (sum of protons and neutrons). - The subscript \(2\) indicates the atomic number (number of protons). - The other product is currently unknown and represented by a question mark (?). ### Completing the Nuclear Reaction To balance this nuclear equation in terms of both mass number and atomic number, we must determine the missing product. 1. **Mass Number Balance:** - Total mass number on the left side (Reactants): \(127\) - Helium-4 (He) has a mass number of \(4\), so: \[ 127 = 4 + \text{Mass number of unknown product} \] \[ \text{Mass number of unknown product} = 127 - 4 = 123 \] 2. **Atomic Number Balance:** - Total atomic number on the left side (Reactants): \(55\) - Helium-4 (He) has an atomic number of \(2\), so: \[ 55 = 2 + \text{Atomic number of unknown product} \] \[ \text{Atomic number of unknown product} = 55 - 2 = 53 \] Thus, the missing product will have a mass number of \(123\) and an atomic number of \(53\). The element with atomic number \(53\) is Iodine (symbol I). ### Completed Nuclear Reaction The completed nuclear reaction is: \[ \,^{127}_{55}\text{Cs} \rightarrow \,^{4}_{2}\text{
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