8. He + 27AI ---→ H + 2 13

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Complete the nuclear equation and identify the missing particle
**Problem 8: Nuclear Reaction**

The equation represents a nuclear reaction in which a Helium-4 nucleus (⁴₂He) collides with an Aluminum-27 nucleus (²⁷₁₃Al). The products of this reaction include a Hydrogen-1 nucleus (¹₁H) and another particle that needs to be identified.

**Equation:**

\[ ⁴₂He + ²⁷₁₃Al \rightarrow ¹₁H + ? \]

To identify the missing particle, we need to balance both the mass numbers (superscripts) and the atomic numbers (subscripts) on both sides of the equation.

**Balancing Mass Numbers:**

On the left side:
\[ 4 + 27 = 31 \]

On the right side:
\[ 1 + ?_{\text{mass number}} \]

Thus,
\[ 1 + ?_{\text{mass number}} = 31 \]
\[ ?_{\text{mass number}} = 31 - 1 = 30 \]

**Balancing Atomic Numbers:**

On the left side:
\[ 2 + 13 = 15 \]

On the right side:
\[ 1 + ?_{\text{atomic number}} \]

Thus,
\[ 1 + ?_{\text{atomic number}} = 15 \]
\[ ?_{\text{atomic number}} = 15 - 1 = 14 \]

Therefore, the missing particle has a mass number of 30 and an atomic number of 14, which corresponds to Silicon-30 (³⁰₁₄Si).

**Complete Equation:**

\[ ⁴₂He + ²⁷₁₃Al \rightarrow ¹₁H + ³⁰₁₄Si \]
Transcribed Image Text:**Problem 8: Nuclear Reaction** The equation represents a nuclear reaction in which a Helium-4 nucleus (⁴₂He) collides with an Aluminum-27 nucleus (²⁷₁₃Al). The products of this reaction include a Hydrogen-1 nucleus (¹₁H) and another particle that needs to be identified. **Equation:** \[ ⁴₂He + ²⁷₁₃Al \rightarrow ¹₁H + ? \] To identify the missing particle, we need to balance both the mass numbers (superscripts) and the atomic numbers (subscripts) on both sides of the equation. **Balancing Mass Numbers:** On the left side: \[ 4 + 27 = 31 \] On the right side: \[ 1 + ?_{\text{mass number}} \] Thus, \[ 1 + ?_{\text{mass number}} = 31 \] \[ ?_{\text{mass number}} = 31 - 1 = 30 \] **Balancing Atomic Numbers:** On the left side: \[ 2 + 13 = 15 \] On the right side: \[ 1 + ?_{\text{atomic number}} \] Thus, \[ 1 + ?_{\text{atomic number}} = 15 \] \[ ?_{\text{atomic number}} = 15 - 1 = 14 \] Therefore, the missing particle has a mass number of 30 and an atomic number of 14, which corresponds to Silicon-30 (³⁰₁₄Si). **Complete Equation:** \[ ⁴₂He + ²⁷₁₃Al \rightarrow ¹₁H + ³⁰₁₄Si \]
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