Rb ? + 37

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Chapter1: Chemical Foundations
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Complete each nuclear equation.

 

This image represents a nuclear reaction involving Rubidium-87 (\(_{37}^{87}\text{Rb}\)) undergoing a decay process. The equation is as follows:

\(_{37}^{87}\text{Rb} \rightarrow ? + _{-1}^{0}\beta\)

Here's a detailed breakdown of the equation:

- The left side of the equation shows the initial isotope: Rubidium-87 (\(_{37}^{87}\text{Rb}\)), where 37 is the atomic number and 87 is the mass number.
- The right side shows the products of this decay:
  - One of the products is represented by a question mark. To determine what the mystery product is, we need to balance both the atomic and mass numbers on both sides of the equation.
  - The other product is a beta particle (\(_{-1}^{0}\beta\)), indicating that a neutron in the nucleus has transformed into a proton, releasing a beta particle.
  
In beta decay, the atomic number of the product increases by 1 (since a neutron converts into a proton), and the mass number remains the same. Thus, the mystery element on the right side can be identified as Strontium-87 (\(_{38}^{87}\text{Sr}\)).

The complete equation looks like this:

\(_{37}^{87}\text{Rb} \rightarrow _{38}^{87}\text{Sr} + _{-1}^{0}\beta\)

In summary, Rubidium-87 decays into Strontium-87 and a beta particle.
Transcribed Image Text:This image represents a nuclear reaction involving Rubidium-87 (\(_{37}^{87}\text{Rb}\)) undergoing a decay process. The equation is as follows: \(_{37}^{87}\text{Rb} \rightarrow ? + _{-1}^{0}\beta\) Here's a detailed breakdown of the equation: - The left side of the equation shows the initial isotope: Rubidium-87 (\(_{37}^{87}\text{Rb}\)), where 37 is the atomic number and 87 is the mass number. - The right side shows the products of this decay: - One of the products is represented by a question mark. To determine what the mystery product is, we need to balance both the atomic and mass numbers on both sides of the equation. - The other product is a beta particle (\(_{-1}^{0}\beta\)), indicating that a neutron in the nucleus has transformed into a proton, releasing a beta particle. In beta decay, the atomic number of the product increases by 1 (since a neutron converts into a proton), and the mass number remains the same. Thus, the mystery element on the right side can be identified as Strontium-87 (\(_{38}^{87}\text{Sr}\)). The complete equation looks like this: \(_{37}^{87}\text{Rb} \rightarrow _{38}^{87}\text{Sr} + _{-1}^{0}\beta\) In summary, Rubidium-87 decays into Strontium-87 and a beta particle.
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