b. Compound 4.2 was reacted with Br₂ in H₂O and three compounds were observed after completion of the following reaction: CH3 4.2 Br₂ H₂O Table 4.1 summarises the yield and molecular formula of the products (Compounds 4.3, 4.4 and 4.5). 4.4 Table 4.1: The yields of Compounds 4.3, 4.4 and 4.5. Compound 4.3 4.5 Yield/% 90 4.3, 4.4 and 4.5 8 2 Molecular formula C11H13 OBr C11H13OBr C11H12Br2

b. Compound 4.2 was reacted with Br₂ in H₂O and three compounds were observed after completion of the following reaction: CH3 4.2 Br₂ H₂O Table 4.1 summarises the yield and molecular formula of the products (Compounds 4.3, 4.4 and 4.5). 4.4 Table 4.1: The yields of Compounds 4.3, 4.4 and 4.5. Compound 4.3 4.5 Yield/% 90 4.3, 4.4 and 4.5 8 2 Molecular formula C11H13 OBr C11H13OBr C11H12Br2

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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6. In the molecular weight determination by the Dumas method, as illustrated below, several grams of an organic liquid were drawn into the bulb. The bulb was then immersed in a water bath at 87 C and kept there until all the liquid was vaporized and the air in the bulb was replaced by the vapor. The tip was then sealed shut and the bulb removed from the bath, cooled, dried and weighed at room temperature. The weight of the bulb filled with the vapor was 36.127 g; the weight of the empty (evacuated) bulb was 35.427 g; the bulb's volume was 200.0 mL; room temperature was 25°C; and the barometric pressure was 720 mm Hg. Calculate the molecular weight of the organic liquid.
5:38 PM Tue Nov 9 * 100 Question 22 of 22 Consider the balanced chemical reaction below. Calculate the percent yield for the reaction... MnO, + 4HCI → MnCl2 + Cl2 + 2H,0 2 NEXT > The reaction was started with 1.00 mol of MnO, and 95.0 g of HCI (MW 36.458 g/mol). Set up the table below that represents 100% yield with the given reaction conditions. Ignore the water side product. MnO2 4HCI -> MnCl2 Cl2 Before (mol) Change (mol) After (mol) 2 RESET 1.00 95.0 -95.0 2.61 -2.61 0.625 -0.625 0.375 -0.375 4.00 -4.00 Tap here or pull up for additional resources
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