b. Compound 4.2 was reacted with Br₂ in H₂O and three compounds were observed after completion of the following reaction: CH3 4.2 Br₂ H₂O Table 4.1 summarises the yield and molecular formula of the products (Compounds 4.3, 4.4 and 4.5). 4.4 Table 4.1: The yields of Compounds 4.3, 4.4 and 4.5. Compound 4.3 4.5 Yield/% 90 4.3, 4.4 and 4.5 8 2 Molecular formula C11H13 OBr C11H13OBr C11H12Br2

b. Compound 4.2 was reacted with Br₂ in H₂O and three compounds were observed after completion of the following reaction: CH3 4.2 Br₂ H₂O Table 4.1 summarises the yield and molecular formula of the products (Compounds 4.3, 4.4 and 4.5). 4.4 Table 4.1: The yields of Compounds 4.3, 4.4 and 4.5. Compound 4.3 4.5 Yield/% 90 4.3, 4.4 and 4.5 8 2 Molecular formula C11H13 OBr C11H13OBr C11H12Br2

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Calculate theroetical yield in BOTH grams and mols and percent yield (% by mass) please!
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5:38 PM Tue Nov 9 * 100 Question 22 of 22 Consider the balanced chemical reaction below. Calculate the percent yield for the reaction... MnO, + 4HCI → MnCl2 + Cl2 + 2H,0 2 NEXT > The reaction was started with 1.00 mol of MnO, and 95.0 g of HCI (MW 36.458 g/mol). Set up the table below that represents 100% yield with the given reaction conditions. Ignore the water side product. MnO2 4HCI -> MnCl2 Cl2 Before (mol) Change (mol) After (mol) 2 RESET 1.00 95.0 -95.0 2.61 -2.61 0.625 -0.625 0.375 -0.375 4.00 -4.00 Tap here or pull up for additional resources
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