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B Rec RAB RG I H I3 G RcD RAD Vo F K

B Rec RAB RG I H I3 G RcD RAD Vo F K

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Apply the Loop Rule to BCDHB.

### Wheatstone Bridge Circuit Diagram The diagram represents a Wheatstone Bridge, an electrical circuit used to precisely measure an unknown resistance by balancing two legs of a bridge circuit. The primary components and paths are described below: - **Resistances:** - \( R_{AB} \): Resistance between points A and B. - \( R_{BC} \): Resistance between points B and C. - \( R_{CD} \): Resistance between points C and D. - \( R_{AD} \): Resistance between points A and D. - \( R_G \): Galvanometer resistance between points B and D. - **Current Paths:** - \( I_1 \): Current flowing from point A to point B through resistance \( R_{AB} \). - \( I_2 \): Current flowing from point A to point D through resistance \( R_{AD} \). - \( I_3 \): Current flowing through the galvanometer \( G \) between points B and D. - **Key Points:** - **A, B, C, D**: Junction points in the circuit. - **H**: Junction point for galvanometer connection. - **G**: Galvanometer at point H for detecting current. - **Circuit Path:** - The power source provides voltage \( V_o \) between points F and K, with the positive terminal at F and negative at K. This setup is typically used to find the unknown resistance by adjusting until the galvanometer shows no current (\( I_3 = 0 \)), indicating a balanced bridge where \( \frac{R_{AB}}{R_{BC}} = \frac{R_{AD}}{R_{CD}} \).
Transcribed Image Text:### Wheatstone Bridge Circuit Diagram The diagram represents a Wheatstone Bridge, an electrical circuit used to precisely measure an unknown resistance by balancing two legs of a bridge circuit. The primary components and paths are described below: - **Resistances:** - \( R_{AB} \): Resistance between points A and B. - \( R_{BC} \): Resistance between points B and C. - \( R_{CD} \): Resistance between points C and D. - \( R_{AD} \): Resistance between points A and D. - \( R_G \): Galvanometer resistance between points B and D. - **Current Paths:** - \( I_1 \): Current flowing from point A to point B through resistance \( R_{AB} \). - \( I_2 \): Current flowing from point A to point D through resistance \( R_{AD} \). - \( I_3 \): Current flowing through the galvanometer \( G \) between points B and D. - **Key Points:** - **A, B, C, D**: Junction points in the circuit. - **H**: Junction point for galvanometer connection. - **G**: Galvanometer at point H for detecting current. - **Circuit Path:** - The power source provides voltage \( V_o \) between points F and K, with the positive terminal at F and negative at K. This setup is typically used to find the unknown resistance by adjusting until the galvanometer shows no current (\( I_3 = 0 \)), indicating a balanced bridge where \( \frac{R_{AB}}{R_{BC}} = \frac{R_{AD}}{R_{CD}} \).
Use Kirchhoff’s junction rule and voltage/loop rule to find the current through each resistor in the following circuit: \( R_{AB} = 10 \, \Omega \), \( R_{BC} = 15 \, \Omega \), \( R_{AD} = 6 \, \Omega \), \( R_{CD} = 12 \, \Omega \), \( R_{G} = 4 \, \Omega \), and \( V_o = 10 \, \text{V} \).
Transcribed Image Text:Use Kirchhoff’s junction rule and voltage/loop rule to find the current through each resistor in the following circuit: \( R_{AB} = 10 \, \Omega \), \( R_{BC} = 15 \, \Omega \), \( R_{AD} = 6 \, \Omega \), \( R_{CD} = 12 \, \Omega \), \( R_{G} = 4 \, \Omega \), and \( V_o = 10 \, \text{V} \).
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