B M 1 HO d.d. 3. OH N OH OH M OH OH P What is the product of hydroboration-oxidation of substrate L? Justify your answer. Product N, because hydroboration follows an anti-Markovnikov orientation by placing the H on the most substituted side and the OH on the least substituted side of the of the double bond in the substrate. Product P. because hydroboration follows an anti-Markovnikov orientation by placing the H on the most substituted side and the OH on the least substituted side of the of the double bond in the substrate. Product Q, because hydroboration follows a Markovnikov orientation by placing the H on the most substituted side and the OH on the least substituted side of the of the double bond in the substrate.

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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G.122.

 

B
M
21
HO
d.d. 3.
OH
N
M
OH
OH
OH
8. 8.
P
What is the product of hydroboration-oxidation of substrate L? Justify your answer.
Product N, because hydroboration follows an anti-Markovnikov orientation by
placing the H on the most substituted side and the OH on the least substituted
side of the of the double bond in the substrate.
Product P. because hydroboration follows an anti-Markovnikov orientation by
placing the H on the most substituted side and the OH on the least substituted
side of the of the double bond in the substrate.
Product Q, because hydroboration follows a Markovnikov orientation by placing
the H on the most substituted side and the OH on the least substituted side of
the of the double bond in the substrate.
Transcribed Image Text:B M 21 HO d.d. 3. OH N M OH OH OH 8. 8. P What is the product of hydroboration-oxidation of substrate L? Justify your answer. Product N, because hydroboration follows an anti-Markovnikov orientation by placing the H on the most substituted side and the OH on the least substituted side of the of the double bond in the substrate. Product P. because hydroboration follows an anti-Markovnikov orientation by placing the H on the most substituted side and the OH on the least substituted side of the of the double bond in the substrate. Product Q, because hydroboration follows a Markovnikov orientation by placing the H on the most substituted side and the OH on the least substituted side of the of the double bond in the substrate.
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