A 5.276 g sample of Al-Mg alloy is digested in nitric acid (to Al*3 and Mg*²). The solution is diluted to 500.00 mL and three 100.00 mL aliquots are treated with ammonia, the resulting Al(OH)3 precipitate is dried and then ignited to alumina, Al2O3 (MM = 101.961 g/mol). If the average mass of alumina obtained was 1.444 g, what was the percentage of aluminum (MM = 26.9815 g/mol) in the original sample?

A 5.276 g sample of Al-Mg alloy is digested in nitric acid (to Al3 and Mg²). The solution is diluted to 500.00 mL and three 100.00 mL aliquots are treated with ammonia, the resulting Al(OH)3 precipitate is dried and then ignited to alumina, Al2O3 (MM = 101.961 g/mol). If the average mass of alumina obtained was 1.444 g, what was the percentage of aluminum (MM = 26.9815 g/mol) in the original sample?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

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6. A 5.276 g sample of Al-Mg alloy is digested in nitric acid (to Al*3 and Mg*?). The solution is diluted to
500.00 mL and three 100.00 mL aliquots are treated with ammonia, the resulting Al(OH)3 precipitate is
dried and then ignited to alumina, Al2O; (MM = 101.961 g/mol). If the average mass of alumina
obtained was 1.444 g, what was the percentage of aluminum (MM = 26.9815 g/mol) in the original
sample?

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