Answer for Question B) (B) is there an effect due to the type of course?Answer: Since F < Fcrit, then we_____________ the null hypothesis. This means the data do not indicate that a difference exists between the average amounts for the two types of courses. None seems superior to the others. Pregunta 8A nationwide company specializing in preparing students for college and graduate school entrance exams, such as the SAT, ACT, andLSAT, had the business objective of improving its ACT preparatory course. Two factors of interest to the company are the length ofthe course (a condensed 10-day period or a regular 30-day period) and the type of course (traditional classroom or online distancelearning). The company collected data by randomly assigning 10 clients to each of the four cells that represent a combination oflength of the course and type of course. The results are organized and presented in the following table:LENGTH OF COURSETYPE OF COURSECondensedRegularTraditional26 1834 2827 2424 2125 1935 2321 2031 2921 1828 26Online27 2124 2129 3216 1930 2022 1924 2820 2430 2923 25The two-way ANOVA results are (Factor A (columns) is the lenght, factor B (sample) is the type of course)B C DE FGA1 ANOVA: Two-factor With Replication3 SUMMARYCondensed Regular Total4.traditional5 Count6 Sum7 Average8 Variance10102021927949821.927.924.911.2111 20.9889 24.726310online11 Count10102012 Sum27021348313 Average2721.324.1514 Variance16.2222 8.0111 20.02891516Tulul17 Count202018 Sum48919219 Average20 Variance24.4524.619.8395 25.2000212223 ANOVA24 Source of Variation25 Sample26 ColumnsSSdfMSP-value r crit5.625015.6250 0.3987 0.5318 4,11321 0.2250 0.0159 0.9002 4.11321 342.2250 24.2560 0.0000 4.11320.225027 Interaction342.225028 Within507.900036 14.10832930 Total31855.9750Level of significance 0.05What are the effects of the type of course and the length of the course on ACT scores?To answer, at the 0.05 level of significance,(A) is there an interaction between the type of course and the length of the course?Answer: Since F -24.2560 > Fcrit, then wethe null hypothesis.Thus, the hypothesis test confirms the interaction evident in the cell means plot. The existence of this significant interaction effectcomplicates the interpretation of the hypothesis tests concerning the two main effects, so we need to perform a One-way Anova tocomplete the analysis.(B) is there an effect due to the type of course?Answer: Since F< Fcrit, then wethe null hypothesis. This means the data do not indicate that a difference existsbetween the average amounts for the two types of courses. None seems superior to the others.

B) The F-statistic value is less than the F critical value.

(B) is there an effect due to the type of course? Answer: Since F < Fcrit, then we_____________ the null hypothesis. This means the data do not indicate that a difference exists between the average amounts for the two types of courses. None seems superior to the others.

(B) is there an effect due to the type of course? Answer: Since F < Fcrit, then we_____________ the null hypothesis. This means the data do not indicate that a difference exists between the average amounts for the two types of courses. None seems superior to the others.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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3.5 GRE scores, Part II: In Exercise 3.3 we saw two distributions for GRE scores: N(H=151,0=7) for the verbal section of the exam and N(u=153, o=7.67) for the quantitative section. Use this information to compute each of the following. Round all your answers to 2 decimal places. a) The score of a student who scored in the 75-th percentile on the Quantitative Reasoning section. b) The score of a student who scored worse than 70% of the test takers in the Verbal Reasoning section.
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Item9 eBook Item 9 The following regression output was obtained from a study of architectural firms. The dependent variable is the total amount of fees in millions of dollars. Predictor Coefficient SE Coefficient t p-value Constant 9.601 3.153 3.045 0.010 x1 0.221 0.110 2.009 0.000 x2 − 1.168 0.577 − 2.024 0.028 x3 − 0.106 0.073 − 1.452 0.114 x4 0.631 0.361 1.748 0.001 x5 − 0.043 0.029 − 1.483 0.112 Analysis of Variance Source DF SS MS F p-value Regression 5 1,844.31 368.9 9.37 0.000 Residual Error 56 2,205.62 39.39 Total 61 4,049.93 x1 is the number of architects employed by the company. x2 is the number of engineers employed by the company. x3 is the number of years involved with health care projects. x4 is the number of states in which the firm operates. x5 is the percent of the firm’s work that is health…