b) Consider the case where the angle 0 is 16.8° and the penguin is not moving relative to the ground. Using Newton's Second Law of Motion [and the free-body diagram from part (a)], determine the force of friction on the penguin. Note that the solution for the force of friction should be written in unit vector notation using the rotated coordinate system. Assume the mass of the penguin is 5.11 kg and that g = 9.81 m/s?. Answer in units of N with 3 sig figs. Hint: force of friction, fs us N, as this expression gives us the maximum force of static friction that is possible, not necessarily the force of friction that is present.
b) Consider the case where the angle 0 is 16.8° and the penguin is not moving relative to the ground. Using Newton's Second Law of Motion [and the free-body diagram from part (a)], determine the force of friction on the penguin. Note that the solution for the force of friction should be written in unit vector notation using the rotated coordinate system. Assume the mass of the penguin is 5.11 kg and that g = 9.81 m/s?. Answer in units of N with 3 sig figs. Hint: force of friction, fs us N, as this expression gives us the maximum force of static friction that is possible, not necessarily the force of friction that is present.
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Transcribed Image Text:A penguin of mass, m, is on an inclined surface (hill), as shown in the diagram. The inclined surface is at
an angle of 0 from the flat ground. The coefficient of static friction, µs = 0.498 and the coefficient of
kinetic friction, H; = 0.295. Also assume there is a force from gravity (i.e. the weight, W = mg, is pointed
straight down towards the ground, as always).
![b) Consider the case where the angle 0 is 16.8° and the penguin is not moving relative to the
ground. Using Newton's Second Law of Motion [and the free-body diagram from part (a)],
determine the force of friction on the penguin. Note that the solution for the force of friction
should be written in unit vector notation using the rotated coordinate system. Assume the mass
of the penguin is 5.11 kg and that g = 9.81 m/s?. Answer in units of N with 3 sig figs. Hint: force
of friction, fs us N, as this expression gives us the maximum force of static friction that is
possible, not necessarily the force of friction that is present.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1e48e704-0f6b-4d35-a17c-aafc95ca01b5%2Fa96d9804-d5e5-4b1d-a445-d73430ef97ae%2Fqv6pl2u_processed.png&w=3840&q=75)
Transcribed Image Text:b) Consider the case where the angle 0 is 16.8° and the penguin is not moving relative to the
ground. Using Newton's Second Law of Motion [and the free-body diagram from part (a)],
determine the force of friction on the penguin. Note that the solution for the force of friction
should be written in unit vector notation using the rotated coordinate system. Assume the mass
of the penguin is 5.11 kg and that g = 9.81 m/s?. Answer in units of N with 3 sig figs. Hint: force
of friction, fs us N, as this expression gives us the maximum force of static friction that is
possible, not necessarily the force of friction that is present.
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