b) Consider the case where the angle 0 is 16.8° and the penguin is not moving relative to the ground. Using Newton's Second Law of Motion [and the free-body diagram from part (a)], determine the force of friction on the penguin. Note that the solution for the force of friction should be written in unit vector notation using the rotated coordinate system. Assume the mass of the penguin is 5.11 kg and that g = 9.81 m/s?. Answer in units of N with 3 sig figs. Hint: force of friction, f; µs N, as this expression gives us the maximum force of static friction that is possible, not necessarily the force of friction that is present.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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b) Consider the case where the angle e is 16.8° and the penguin is not moving relative to the
ground. Using Newton's Second Law of Motion [and the free-body diagram from part (a)],
determine the force of friction on the penguin. Note that the solution for the force of friction
should be written in unit vector notation using the rotated coordinate system. Assume the mass
of the penguin is 5.11 kg and that g = 9.81 m/s?. Answer in units of N with 3 sig figs. Hint: force
of friction, f. + µs N, as this expression gives us the maximum force of static friction that is
possible, not necessarily the force of friction that is present.
Transcribed Image Text:b) Consider the case where the angle e is 16.8° and the penguin is not moving relative to the ground. Using Newton's Second Law of Motion [and the free-body diagram from part (a)], determine the force of friction on the penguin. Note that the solution for the force of friction should be written in unit vector notation using the rotated coordinate system. Assume the mass of the penguin is 5.11 kg and that g = 9.81 m/s?. Answer in units of N with 3 sig figs. Hint: force of friction, f. + µs N, as this expression gives us the maximum force of static friction that is possible, not necessarily the force of friction that is present.
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