b Answered: E Enthalpy - Chemistry X 101 Chem101 app.101edu.co Submit Question 22 of 29 Using the equations 2 C6H6 (1) + 15 O2 (g) C (s) + O2 (g) → CO2 (g) AH° = -393.5 kJ/mol 2 H2 (g) + O2 (g) → 2 H2O (g) AH° = -483.6 kJ/mol Determine the enthalpy for the reaction 6 C (s) + 3 H2 (g) → C6H6 (1). → 12 CO2 (g) + 6 H2O (g)AH° = -6271 kJ/mol kJ/mol 1 3 4 9. +/- x 100 8:49 PM O Type here to search 3. 12/8/2019 LO 00

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b Answered: E Enthalpy - Chemistry X
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Question 22 of 29
Using the equations
2 C6H6 (1) + 15 O2 (g)
C (s) + O2 (g) → CO2 (g) AH° = -393.5 kJ/mol
2 H2 (g) + O2 (g) → 2 H2O (g) AH° = -483.6 kJ/mol
Determine the enthalpy for the reaction
6 C (s) + 3 H2 (g) → C6H6 (1).
→ 12 CO2 (g) + 6 H2O (g)AH° = -6271 kJ/mol
kJ/mol
1
3
4
9.
+/-
x 100
8:49 PM
O Type here to search
3.
12/8/2019
LO
00
Transcribed Image Text:b Answered: E Enthalpy - Chemistry X 101 Chem101 app.101edu.co Submit Question 22 of 29 Using the equations 2 C6H6 (1) + 15 O2 (g) C (s) + O2 (g) → CO2 (g) AH° = -393.5 kJ/mol 2 H2 (g) + O2 (g) → 2 H2O (g) AH° = -483.6 kJ/mol Determine the enthalpy for the reaction 6 C (s) + 3 H2 (g) → C6H6 (1). → 12 CO2 (g) + 6 H2O (g)AH° = -6271 kJ/mol kJ/mol 1 3 4 9. +/- x 100 8:49 PM O Type here to search 3. 12/8/2019 LO 00
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