b Answered: E Enthalpy - Chemistry X 101 Chem101 app.101edu.co Submit Question 22 of 29 Using the equations 2 C6H6 (1) + 15 O2 (g) C (s) + O2 (g) → CO2 (g) AH° = -393.5 kJ/mol 2 H2 (g) + O2 (g) → 2 H2O (g) AH° = -483.6 kJ/mol Determine the enthalpy for the reaction 6 C (s) + 3 H2 (g) → C6H6 (1). → 12 CO2 (g) + 6 H2O (g)AH° = -6271 kJ/mol kJ/mol 1 3 4 9. +/- x 100 8:49 PM O Type here to search 3. 12/8/2019 LO 00

b Answered: E Enthalpy - Chemistry X 101 Chem101 app.101edu.co Submit Question 22 of 29 Using the equations 2 C6H6 (1) + 15 O2 (g) C (s) + O2 (g) → CO2 (g) AH° = -393.5 kJ/mol 2 H2 (g) + O2 (g) → 2 H2O (g) AH° = -483.6 kJ/mol Determine the enthalpy for the reaction 6 C (s) + 3 H2 (g) → C6H6 (1). → 12 CO2 (g) + 6 H2O (g)AH° = -6271 kJ/mol kJ/mol 1 3 4 9. +/- x 100 8:49 PM O Type here to search 3. 12/8/2019 LO 00

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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The enthalpy change for the oxidation of butane, C4H₁0, is measured by calorimetry. C4H10 (g) + 13/2 O2(g) → 4 CO2 (g) +5 H₂O(l) A₂H = -2877.6 kJ/mol-rxn Use this value, along with the standard enthalpies of formation of CO2(g) and H₂O(l) (-393.509 kJ/mol and -285.83 kJ/mol respectively), to calculate the enthalpy of formation of butane, C4H10, in kJ/mol. Enthalpy of formation = Submit Answer OCT 30 Try Another Version tv kJ/mol S4 I all 9 item attempts remaining Cengage Learning | Cengage Technical Support A MacBook Pro 7 ( O 04
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