Calculate the pZn2+ for solutions prepared by adding 5.00, 10.00, and 15.00 ml of 0.0200 M EDTA to30.00 ml of 0.0100 M Zn2*. Assume that both the Zn2* and EDTA are 0.0100 M in NH3 to provide aconstant pH of 9.0.ayt = 5.0 x 102OZna+ = 1.17 x 10-5K Zaya- = 3.0 x 101618. pZn2+ at 5.00 mL EDTAAnswer: [ Select]19. pZn2* at 10.00 mL EDTAAnswer: [ Select]20. pZn2+ at 15.00 mL EDTAAns[ Select ]>

Answered: Image /qna-images/answer/926dddae-6dfa-44a2-81ad-3c14fb83c7bc.jpg

Answered: aye = 5.0 x 10 2 Zna+ = 1.17 x 10-5…

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aye = 5.0 x 10 2 Zna+ = 1.17 x 10-5 Znya-= 3.0 x 1016

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Calculate the pZn2+ for solutions prepared by adding 5.00, 10.00, and 15.00 ml of 0.0200 M EDTA to
30.00 ml of 0.0100 M Zn2*. Assume that both the Zn2* and EDTA are 0.0100 M in NH3 to provide a
constant pH of 9.0.
ayt = 5.0 x 102
OZna+ = 1.17 x 10-5
K Zaya- = 3.0 x 1016
18. pZn2+ at 5.00 mL EDTA
Answer: [ Select]
19. pZn2* at 10.00 mL EDTA
Answer: [ Select]
20. pZn2+ at 15.00 mL EDTA
Ans
[ Select ]
>

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