Athlete hasNot stretchedUse the contingency table to the right to calculate the marginal frequencies and find the expected frequency for each cell inthe contingency table. Assume that the variables are independent.ResultStretchedInjuryNo injury2229222177(a) Calculate the marginal frequencies and sample size.Athlete hasResultStretchedNot stretchedTotalInjury222951No injury222177399Total244206450(b) Find the expected frequency for each cell in the contingency table.Athlete hasStretchedNot stretchedResultInjuryNo injury(Round to two decimal places as needed.)

Answered: Image /qna-images/answer/a24f1cae-b2dc-4d27-835e-3ee7591b0342.jpg

Answered: Athlete has Use the contingency table…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Actuaries use various parameters when evaluating the cost of a life insurance policy. The variance of the life spans of a population is one of the parameters used for the evaluation. Each year, the actuaries at a particular insurance company randomly sample 30 people who died during the year (with the samples chosen independently from year to year) to see whether the variance of life spans has changed. The life span data from this year and from last year are summarized below. Current Last Year Year *1 = 75.8 x2 = 76.2 s3 = 47.61 s3= 92.16 (The first row gives the sample means and the second row gives the sample variances.) Assume that life spans are approximately normally distributed for each of the populations of people who died this year and people who died last year. Can we conclude, at the 0.05 significance level, that the variance of the life span for the current year, of, differs from the variance of the life span for last year, o,? Perform a two-tailed test. Then complete the…
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