At a certain temperature, the equilibrium constant K for the following reaction is 575.: H₂(g) + 1₂(g) → 2 HI(g) Use this information to complete the following table. Suppose a 44. L reaction vessel is filled with 0.64 mol of HI. What can you say about the composition of the mixture in the vessel at equilibrium? What is the equilibrium constant for the following reaction? Round your answer to 3 significant digits. 2 HI(g) P H₂(9) + 1₂ (9) What is the equilibrium constant for the following reaction? Round your answer to 3 significant digits. 3 H₂(9)+31₂(9) 6 HI(9) There will be very little H₂ and I2. There will be very little HI. Neither of the above is true. K = 0 K = 0

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At a certain temperature, the equilibrium constant K for the following reaction is 575.:
H₂(g) + 1₂(g) → 2 HI(g)
Use this information to complete the following table.
Suppose a 44. L reaction vessel is filled with 0.64 mol of HI.
What can you say about the composition of the mixture in the
vessel at equilibrium?
What is the equilibrium constant for the following reaction?
Round your answer to 3 significant digits.
2 HI(g)
H₂(9) + 1₂ (9)
What is the equilibrium constant for the following reaction?
Round your answer to 3 significant digits.
3 H₂(g)+31₂(9)
6 HI(g)
There will be very little H₂ and 12.
There will be very little HI.
Neither of the above is true.
K = 0
-0
K =
Transcribed Image Text:At a certain temperature, the equilibrium constant K for the following reaction is 575.: H₂(g) + 1₂(g) → 2 HI(g) Use this information to complete the following table. Suppose a 44. L reaction vessel is filled with 0.64 mol of HI. What can you say about the composition of the mixture in the vessel at equilibrium? What is the equilibrium constant for the following reaction? Round your answer to 3 significant digits. 2 HI(g) H₂(9) + 1₂ (9) What is the equilibrium constant for the following reaction? Round your answer to 3 significant digits. 3 H₂(g)+31₂(9) 6 HI(g) There will be very little H₂ and 12. There will be very little HI. Neither of the above is true. K = 0 -0 K =
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