At a certain temperature, 0.88 mol N₂ and 2.654 mol H₂ are placed in a container. N₂(g) + 3H₂(g) = 2NH3(g) At equilibrium, there is 0.82 mol NH3 present. Determine the number of moles of N₂ and H₂ that are present when the reaction is at equilibrium. moles of N₂ at equilibrium: moles of H₂ at equilibrium: mol mol

At a certain temperature, 0.88 mol N₂ and 2.654 mol H₂ are placed in a container. N₂(g) + 3H₂(g) = 2NH3(g) At equilibrium, there is 0.82 mol NH3 present. Determine the number of moles of N₂ and H₂ that are present when the reaction is at equilibrium. moles of N₂ at equilibrium: moles of H₂ at equilibrium: mol mol

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Suppose a 250. mL flask is filled with 0.40 mol of H₂ and 1.3 mol of HI. This reaction becomes possible: H₂(g) +1₂(g) → 2HI(g) Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of H₂. You can leave out the M symbol for molarity. initial cha equilibrium H₂ 0 X 0 1₂ 0 HI 00 믐 X olo 18 Ar
Suppose a 500. mL flask is filled with 1.6 mol of H₂ and 0.30 mol of HI. This reaction becomes possible: H₂(g) + 12₂(g) → 2HI(g) Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of I2. You can leave out the M symbol for molarity. initial change equilibrium H₂ 0 1₂ x 0 HI 0 X S
Consider the following equilibrium: N₂O4(g) = 2NO2(g) A 1.00 L container is initially filled with 0.200 mol N₂O4At equilibrium, 0.160 mol NO₂are present. What is the equilibrium concentration of N₂O4? 0.120 mol/L 0. 040 mol/L O.0.160 mol/L 0.080 mol/L 0.100 mol/L
Suppose a 250. mL flask is filled with 0.60 mol of SO₂ and 1.0 mol of SO3. This reaction becomes possible: 2SO₂(g) + O₂(g) — 2SO3(g) Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of O₂. You can leave out the M symbol for molarity. initial change equilibrium SO₂ 0₂ 0 X 0 SO₂ 0 010 X Ś
Suppose a 500. mL flask is filled with 0.30 mol of SO, and 1.2 mol of SO3. This reaction becomes possible: 2SO, (g) +O,(g) 2SO3 Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of O,. You can leave out the M symbol for molarity. so, SO2 O2 initial change equilibrium
Suppose a 500. mL flask is filled with 0.50 mol of N, and 0.90 mol of NO. This reaction becomes possible: N,(8) +O,(g) – 2NO(g) Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of N,. You can leave out the Msymbol for molarity. NO initial change equilibrium
For the chemical equation: SO2(g) + NO2(g) SO3(g) + NO(g) The equilibrium constant at a certain temperature is 8.80. At this temperature, calculate the number of moles of NO2(g) that must be added to 6.20 mol SO2(g) in order to form 4.40 mol SO3(g) at equilibrium.
A student adds 0.600 mol of methane gas, CH4(g) into a 2.00 L container and the methane forms ethyne, C2H2(g) and hydrogen gas, H2(g). At equilibrium, the container was found to contain 0.045 mol/L C2H2.a) Calculate the initial concentration of CH4. Then complete an ICE Table to organize the initial, change and equilibrium concentrations for this equilibrium system. Show any calculations needed. 2CH4(g) ⇄ C2H2(g) + 3H2(g)b) Calculate the equilibrium constant, Keq, for this equilibrium. Show all work.c) What is the equilibrium concentration of H2(g) ?
The following figure is humorous but it emphasizes an important characteristic of either a chemical or physical equilibrium. What is it? We're back! I'm sure glad they evaporated! Then I'm getting out of here! A) Equilibrium occurs when all processes come to an end. B) Equilibrium is temperature independent. · C) Equilibrium is reached when the number of reactant and product molecules is the same. D) Equilibrium is dynamic. E) Equilibrium depends on where you start the process. rch inort sc delete 8. backspa K pause
Carbon disulfide and chlorine react according to the following equation: CS2(g) + 3Ch(g) =S,Cl½(g) + CC1,(g) When 1.14 mol of CS, and 4.80 mol of Clh are placed in a 2.00-L container and allowed to come to equilibrium, the mixture is found to contain 0.650 mol of CC14. How many moles of Cl are present at on equilibrium? Select one: O a. 0.490 mol O b. 2.85 mol O c. 3.50 mol O d. 0.650 mol O e. 1.43 mol e to search F3 F4 F5 F6 FZ FB F9 F10 F11 F12 Prise %24 E R T G H K B N M 立

A mixture of 0.100 mol of SO2 and 0.100 mol of O2 is placed in a reaction container and allowed to react until equilibrium is established. 2 SO2 (g) + O2 (g) -> 2 SO3 At equilibrium, 0.0916 mol of SO3 is present. a. What is the composition of the equilibrium mixture in terms of moles of each substance present? (Hint: Stoichiometry!) b. If the container size is 3.0 L, what is the value of the equilibrium constant?
Suppose a 500. mL flask is filled with 1.4 mol of N, and 1.3 mol of NO. This reaction becomes possible: N,(2) +0,(2)- -2NO(g) Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of N,. You can leave out the M symbol for molarity. N2 O2 NO initial change equilibrium olo