At 500 K in the presence of a copper surface, ethanol decomposes according to the equation C2H5OH(g) →CH3CHO(g)+H2 (g) The pressure of C2H5OH was measured as a function of time and the following data were obtained:   Time(s) PC2H5OH (torr) 0 250. 100. 237 200. 224 300. 211 400. 198 500. 185 Since the pressure of a gas is directly proportional to the concentration of gas, we can express the rate law for a gaseous reaction in terms of partial pressures. Using the above data, deduce the rate law, the integrated rate law, and the value of the rate constant, all in terms of pressure units in atm and time in seconds. Predict the pressure of C2H5OH after 900. s from the start of the reaction. (Hint: To determine the order of the reaction with respect to C2H5OH, compare how the pressure of C2H5OHdecreases with each time listing.)

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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At 500 K in the presence of a copper surface, ethanol decomposes according to the equation

C2H5OH(g) →CH3CHO(g)+H(g)

The pressure of C2H5OH was measured as a function of time and the following data were obtained:

 

Time(s)

PC2H5OH (torr)

0

250.

100.

237

200.

224

300.

211

400.

198

500.

185

Since the pressure of a gas is directly proportional to the concentration of gas, we can express the rate law for a gaseous reaction in terms of partial pressures. Using the above data, deduce the rate law, the integrated rate law, and the value of the rate constant, all in terms of pressure units in atm and time in seconds. Predict the pressure of C2H5OH after 900. s from the start of the reaction. (Hint: To determine the order of the reaction with respect to C2H5OH, compare how the pressure of C2H5OHdecreases with each time listing.)

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