4. 240 mol of an liquid mixture of 30 mol % species M and 70 mol % species E is fed to a flash drum. The mixture comes to equilibrium at 90°C and 1225 mmHg. A liquid stream and vapor stream leaves the process unit. Data for species M: p(T = 90°C) = 500 mmHg Data for species E: pĝ(T = 90°C) = 1950 mmHg A flowchart of the process is shown below. Vapor (2) n₂ = ? YM2 =? Feed (1) Flash Drum T=90°C YE2 = 1 - YM2 n₁ = 240 mol XM1 = 0.300 XE1 = 0.700 P=1225 mmHg Liquid (3) n3 = ? XM3 =? XE3 = 1-XM3 Which species is more volatile, species M or species E? Explain using the data provided. b. Use Raoult's law to determine the mole fraction of species M in streams 2 and 3, YM2 and XM3.
4. 240 mol of an liquid mixture of 30 mol % species M and 70 mol % species E is fed to a flash drum. The mixture comes to equilibrium at 90°C and 1225 mmHg. A liquid stream and vapor stream leaves the process unit. Data for species M: p(T = 90°C) = 500 mmHg Data for species E: pĝ(T = 90°C) = 1950 mmHg A flowchart of the process is shown below. Vapor (2) n₂ = ? YM2 =? Feed (1) Flash Drum T=90°C YE2 = 1 - YM2 n₁ = 240 mol XM1 = 0.300 XE1 = 0.700 P=1225 mmHg Liquid (3) n3 = ? XM3 =? XE3 = 1-XM3 Which species is more volatile, species M or species E? Explain using the data provided. b. Use Raoult's law to determine the mole fraction of species M in streams 2 and 3, YM2 and XM3.
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:4. 240 mol of an liquid mixture of 30 mol % species M and 70 mol % species E is fed to a flash
drum. The mixture comes to equilibrium at 90°C and 1225 mmHg. A liquid stream and vapor
stream leaves the process unit.
Data for species M: PM (T = 90°C) = 500 mmHg
Data for species E: př(T = 90°C) = 1950 mmHg
A flowchart of the process is shown below.
Vapor
(2)
n₂ =?
Feed
(1)
Flash Drum
T=90°C
YM2 =?
YE2 = 1 - YM2
n₁ = 240 mol
XM1 0.300
XE1 = 0.700
=
P=1225 mmHg
Liquid
(3)
n3 = ?
XM3 =?
XE3 = 1-XM3
a. Which species is more volatile, species M or species E? Explain using the data provided.
b. Use Raoult's law to determine the mole fraction of species M in streams 2 and 3, ym² and
XM3.
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