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Steam at 1800 Ibf/in.2 and 1100°F enters a turbine operating at steady state. As shown in the figure, 20% of the entering mass flow is extracted at 600 Ibf/in.2 and 500°F. Heat transfer turbine The rest of the steam exits as a P1 = 1800 lbf/in.² T = 1100°F Turbine saturated vapor at 1 lbf/in.2 The turbine develops a power output of 6.8 X 106 Btu/h. Heat transfer from the turbine to the surroundings occurs at a rate of 5 X 104 Btu/h. Neglecting kinetic and potential energy effects, determine the mass flow rate of the steam entering the turbine in Ib/s. Saturated vapor = 1 lbf/in.2 P3 m2 = 0.20 m1 P2 = 600 lbf/in.? T2 = 500°F %3D

Steam at 1800 Ibf/in.2 and 1100°F enters a turbine operating at steady state. As shown in the figure, 20% of the entering mass flow is extracted at 600 Ibf/in.2 and 500°F. Heat transfer turbine The rest of the steam exits as a P1 = 1800 lbf/in.² T = 1100°F Turbine saturated vapor at 1 lbf/in.2 The turbine develops a power output of 6.8 X 106 Btu/h. Heat transfer from the turbine to the surroundings occurs at a rate of 5 X 104 Btu/h. Neglecting kinetic and potential energy effects, determine the mass flow rate of the steam entering the turbine in Ib/s. Saturated vapor = 1 lbf/in.2 P3 m2 = 0.20 m1 P2 = 600 lbf/in.? T2 = 500°F %3D

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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I have attached a formula sheet which might help.
=!| Treservoir Jirrev 1 1st Law СОР, Carnot T AU +AKE + APE = Q-W dKE dΡΕ 1- T, Closed Systems dU =Q-W dt dt dt | Pav W = 2nd Law do m(s, -s,) = T. Constant Pressure Work W = P(V,-V) dScy dộ +ở dt reservoir / irrev Polytropic Work PV,- PV W =-2" 1-n Open Systems Mass dm dt %3D out VA m = 1st Law V? net out dt 2 2nd Law dt j=1 k=1 Isentropic efficiencies Actual Turbine Work (h,-h,) 7, = Isentropic Turbine Work (h,-h,,) %3D Isentropic Compressor Work (h,, -h,) 1. = Actual Compressor Work %3D (h, - h,) Isentropic Pump Work v,(P-P) 7p = Actual Pump Work %3D (h, -h,)
Transcribed Image Text:=!| Treservoir Jirrev 1 1st Law СОР, Carnot T AU +AKE + APE = Q-W dKE dΡΕ 1- T, Closed Systems dU =Q-W dt dt dt | Pav W = 2nd Law do m(s, -s,) = T. Constant Pressure Work W = P(V,-V) dScy dộ +ở dt reservoir / irrev Polytropic Work PV,- PV W =-2" 1-n Open Systems Mass dm dt %3D out VA m = 1st Law V? net out dt 2 2nd Law dt j=1 k=1 Isentropic efficiencies Actual Turbine Work (h,-h,) 7, = Isentropic Turbine Work (h,-h,,) %3D Isentropic Compressor Work (h,, -h,) 1. = Actual Compressor Work %3D (h, - h,) Isentropic Pump Work v,(P-P) 7p = Actual Pump Work %3D (h, -h,)
Steam at 1800 lbf/in.2 and 1100°F enters a turbine operating at steady state. As shown in the figure, 20% of the entering mass flow is extracted at 600 lbf/in.2 and 500°F. The rest of the steam exits as a Heat transfer turbine P1 = 1800 lbf/in.2 T = 1100°F Turbine saturated vapor at 1 lbf/in.2 The turbine develops a power output of 6.8 X 106 Btu/h. Heat transfer from the turbine to the surroundings occurs at a rate of 5 X 104 Btu/h. Neglecting kinetic and potential energy effects, determine the mass flow rate of the steam entering the turbine in Ib/s. %3D Saturated vapor P3 = 1 lbf/in.2 m2 = 0.20 m1 P2 = 600 lbf/in.2 V T2 = 500°F %3D %3D
Transcribed Image Text:Steam at 1800 lbf/in.2 and 1100°F enters a turbine operating at steady state. As shown in the figure, 20% of the entering mass flow is extracted at 600 lbf/in.2 and 500°F. The rest of the steam exits as a Heat transfer turbine P1 = 1800 lbf/in.2 T = 1100°F Turbine saturated vapor at 1 lbf/in.2 The turbine develops a power output of 6.8 X 106 Btu/h. Heat transfer from the turbine to the surroundings occurs at a rate of 5 X 104 Btu/h. Neglecting kinetic and potential energy effects, determine the mass flow rate of the steam entering the turbine in Ib/s. %3D Saturated vapor P3 = 1 lbf/in.2 m2 = 0.20 m1 P2 = 600 lbf/in.2 V T2 = 500°F %3D %3D
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