At 35°C, K = 1.7 x 10¬° for the reaction 2 NOCI(9) = 2 NO(g)+ Cl2 (g) Calculate the concentrations of all species at equilibrium for each of the following original mixtures. a. 3.8 moles of pure NOCI in a 2.0-L flask (NOCI] = M [NO] = M [Cl2] = M b. 1.0 mole of NOCI and 1.0 mole of NO in a 1.0-L flask [NOCI] = M (NO] = M [Cl2] = M
At 35°C, K = 1.7 x 10¬° for the reaction 2 NOCI(9) = 2 NO(g)+ Cl2 (g) Calculate the concentrations of all species at equilibrium for each of the following original mixtures. a. 3.8 moles of pure NOCI in a 2.0-L flask (NOCI] = M [NO] = M [Cl2] = M b. 1.0 mole of NOCI and 1.0 mole of NO in a 1.0-L flask [NOCI] = M (NO] = M [Cl2] = M
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![At 35°C,
K =
1.7 x 10
-5
for the reaction
2 NOCI(g) = 2 NO(g) + Cl2 (g)
Calculate the concentrations of all species at equilibrium for each of the following original mixtures.
a. 3.8 moles of pure NOC1 in a 2.0-L flask
[NOCI] =
M
[NO] =
M
[Cl2] =
M
b. 1.0 mole of
NOCI and 1.0 mole of
NO in a 1.0-L flask
[NOCI] =
M
[NO] =
M
[Cl2] =
M](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F488059e9-9840-4657-993c-02629fc3cfd9%2F0ef0c575-8ac1-4542-b7be-f492d8f7e542%2Ffxxac9f_processed.png&w=3840&q=75)
Transcribed Image Text:At 35°C,
K =
1.7 x 10
-5
for the reaction
2 NOCI(g) = 2 NO(g) + Cl2 (g)
Calculate the concentrations of all species at equilibrium for each of the following original mixtures.
a. 3.8 moles of pure NOC1 in a 2.0-L flask
[NOCI] =
M
[NO] =
M
[Cl2] =
M
b. 1.0 mole of
NOCI and 1.0 mole of
NO in a 1.0-L flask
[NOCI] =
M
[NO] =
M
[Cl2] =
M
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