forward direction to reach equilibrium. reverse direction to reach equilibrium. m.

Chemistry
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Chapter1: Chemical Foundations
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### Reaction Equilibrium Analysis

Consider the following reaction where \( K_c = 7.00 \times 10^{-5} \) at 673 K:

\[ \text{NH}_4\text{I}(s) \rightleftharpoons \text{NH}_3(g) + \text{HI}(g) \]

A reaction mixture was found to contain \( 5.96 \times 10^{-2} \) moles of \(\text{NH}_4\text{I}(s)\), \( 5.51 \times 10^{-3} \) moles of \(\text{NH}_3(g)\), and \( 8.37 \times 10^{-3} \) moles of \(\text{HI}(g)\), in a 1.00 liter container.

#### Questions:
Is the reaction at equilibrium? If not, what direction must it run in order to reach equilibrium?

- The reaction quotient, \( Q_c \), equals [input box].

- The reaction [selection box]:
  - A. must run in the forward direction to reach equilibrium.
  - B. must run in the reverse direction to reach equilibrium.
  - C. is at equilibrium.

### Explanation:
To determine whether the reaction is at equilibrium, calculate the reaction quotient \( Q_c \) and compare it to \( K_c \). If \( Q_c < K_c \), the reaction will proceed in the forward direction to reach equilibrium. If \( Q_c > K_c \), the reaction needs to go in the reverse direction. If \( Q_c = K_c \), the reaction is at equilibrium.
Transcribed Image Text:### Reaction Equilibrium Analysis Consider the following reaction where \( K_c = 7.00 \times 10^{-5} \) at 673 K: \[ \text{NH}_4\text{I}(s) \rightleftharpoons \text{NH}_3(g) + \text{HI}(g) \] A reaction mixture was found to contain \( 5.96 \times 10^{-2} \) moles of \(\text{NH}_4\text{I}(s)\), \( 5.51 \times 10^{-3} \) moles of \(\text{NH}_3(g)\), and \( 8.37 \times 10^{-3} \) moles of \(\text{HI}(g)\), in a 1.00 liter container. #### Questions: Is the reaction at equilibrium? If not, what direction must it run in order to reach equilibrium? - The reaction quotient, \( Q_c \), equals [input box]. - The reaction [selection box]: - A. must run in the forward direction to reach equilibrium. - B. must run in the reverse direction to reach equilibrium. - C. is at equilibrium. ### Explanation: To determine whether the reaction is at equilibrium, calculate the reaction quotient \( Q_c \) and compare it to \( K_c \). If \( Q_c < K_c \), the reaction will proceed in the forward direction to reach equilibrium. If \( Q_c > K_c \), the reaction needs to go in the reverse direction. If \( Q_c = K_c \), the reaction is at equilibrium.
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