The equilibrium constant for the reaction 2 HF (g) = H2 (g) + F2 (g) is 0.150 at a particular temperature. What is the equilibrium constant for the equation 2 H2 (g) + ½ F2 (g) = HF (g)?

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Chapter1: Chemical Foundations
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The equilibrium constant for the reaction 2 HF (g) ⇌ H₂ (g) + F₂ (g) is 0.150 at a particular temperature. What is the equilibrium constant for the equation ½ H₂ (g) + ½ F₂ (g) ⇌ HF (g)?

### Explanation

The image displays a scientific question about chemical equilibrium constants. A virtual calculator is adjacent to the question, allowing for calculation. The equilibrium constant given is for the reaction involving hydrogen fluoride (HF) forming hydrogen (H₂) and fluorine (F₂) gases. The task is to find the equilibrium constant for the reverse and modified reaction where half a mole of H₂ and half a mole of F₂ form HF gas.
Transcribed Image Text:### Transcription The equilibrium constant for the reaction 2 HF (g) ⇌ H₂ (g) + F₂ (g) is 0.150 at a particular temperature. What is the equilibrium constant for the equation ½ H₂ (g) + ½ F₂ (g) ⇌ HF (g)? ### Explanation The image displays a scientific question about chemical equilibrium constants. A virtual calculator is adjacent to the question, allowing for calculation. The equilibrium constant given is for the reaction involving hydrogen fluoride (HF) forming hydrogen (H₂) and fluorine (F₂) gases. The task is to find the equilibrium constant for the reverse and modified reaction where half a mole of H₂ and half a mole of F₂ form HF gas.
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