At 298 K, what is E (in V) for the electrochemical cell below when [Cd2+] = 4.800 M and[Cu²*]= 0.007 M ?Cd(s) | Cd2*(aq) || Cu²*(aq) | Cu(s)Half-ReactionE° (V)Cl2 (g) + 2e2CГ (аg)1.36Br, (1) + 2e¯ →2B1¯(aq)1.070.80Ag" (ag) + e →Ag(s)Cu²+ (aq) + 2eCu(s)0.342H*(ag) + 2e →H2(g)0.00-0.13Pb2+ (aq) + 2eCd2+ (ag) + 2e →A13+Pb(s)-0.40Cd(s)Al(s)-1.66(aд) + Зе —Be2+(ад) + 2е — Be(s)-1.85Report your answer to 3 significant figures.Your Answer:Answerunits

Nernst equation: E=E∘-0.0591nlogPR

At 298 K, what is E (in V) for the electrochemical cell below when [Cd²"]= 4.800 M and [Cu²*] = 0.007 M ? %3D Cd(s) | Cd²*(aq) || Cu²*(aq) | Cu(s) Half-Reaction E° (V) Cl2 (g) + 2e¯ → 2CГ (ад) 1.36 1.07 Br2 (1) + 2e¯ → 2B1¯(aq) → 0.80 Ag" (aq) + e¯ → Ag(s) Cu²* (aq) + 2e → Cu(s) 2н (aд) + 2е 0.34 0.00 H2(g) Pb2+ (ад) + 2е — Рb(s) -0.13 Cd2+ (aq) + 2e¯ → Cd(s) -0.40 Al3+ (aq) + 3e → Al(s) -1.66 Be2+ (aд) + 2е Вe Be(s) -1.85 Report your answer to 3 significant figures. Your Answer: Answer units

At 298 K, what is E (in V) for the electrochemical cell below when [Cd²"]= 4.800 M and [Cu²] = 0.007 M ? %3D Cd(s) | Cd²(aq) || Cu²(aq) | Cu(s) Half-Reaction E° (V) Cl2 (g) + 2e¯ → 2CГ (ад) 1.36 1.07 Br2 (1) + 2e¯ → 2B1¯(aq) → 0.80 Ag" (aq) + e¯ → Ag(s) Cu² (aq) + 2e → Cu(s) 2н (aд) + 2е 0.34 0.00 H2(g) Pb2+ (ад) + 2е — Рb(s) -0.13 Cd2+ (aq) + 2e¯ → Cd(s) -0.40 Al3+ (aq) + 3e → Al(s) -1.66 Be2+ (aд) + 2е Вe Be(s) -1.85 Report your answer to 3 significant figures. Your Answer: Answer units

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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11. Consider the following reaction and its AG-AGo at 25.00 °C 2Ag(aq)+Cu(s) 2Ag(s)+Cu (aq) AG =-88660 J/mol a. Calculate the standard cell potential, E, for the reaction. b. Calculate the equilibrium constant, K, for the reaction.
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