At 25 o C: 3Pe2 (s) + 2Fe (s) -> 2Fe3+ (aq) + 6Pe- (aq) Eo(Pe2/Pe-) = +0.55 V Eo(Fe3+/Fe) = -0.057 V Calculate the equilibrium constant:

Chemistry & Chemical Reactivity
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Chapter18: Principles Of Chemical Reactivity: Entropy And Free Energy
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At 25 C:

3Pe2 (s) + 2Fe (s) -> 2Fe3+ (aq) + 6Pe(aq)

Eo(Pe2/Pe-) = +0.55 V

Eo(Fe3+/Fe) = -0.057 V

Calculate the equilibrium constant:

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