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HF(g) + H,O() = H,0 (aq)+ F"(aq) K¸ = 1.1 × 10-3 F (aq) + HF(g) = HF; (ag) K= 2.6 × 10 a. Is fluoride in pH 7.00 drinking water more likely to be present as F"(aq) or HF2"(aq)? HF2 (aq) O F(aq) b. What is the equilibrium constant for this equilibrium? Number 2 HFg) + H,0(1) H,0*(aq) + HF; (aq) c. What are the pH and equilibrium concentration of HF2" in a 0.150 M solution of HF? (HF, - Number Number pH -

HF(g) + H,O() = H,0 (aq)+ F"(aq) K¸ = 1.1 × 10-3 F (aq) + HF(g) = HF; (ag) K= 2.6 × 10 a. Is fluoride in pH 7.00 drinking water more likely to be present as F"(aq) or HF2"(aq)? HF2 (aq) O F(aq) b. What is the equilibrium constant for this equilibrium? Number 2 HFg) + H,0(1) H,0*(aq) + HF; (aq) c. What are the pH and equilibrium concentration of HF2" in a 0.150 M solution of HF? (HF, - Number Number pH -

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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HF(g) + H,O(1) H,0*(aq)+ F"(aq) K = 1.1 x 10-3 F (aq) + HF(g) HF;(ag) K= 2.6 x 10- a. Is fluoride in pH 7.00 drinking water more likely to be present as F"(aq) or HF2 (aq)? O HF2 (aq) O F(aq) b. What is the equilibrium constant for this equilibrium? Number 2 HF(g) + H,0(1) H,0*(aq) + HF, (aq) c. What are the pH and equilibrium concentration of HF2" in a 0.150 M solution of HF? (HF, - Number Number pH = M Check Answer View Solution
Transcribed Image Text:HF(g) + H,O(1) H,0*(aq)+ F"(aq) K = 1.1 x 10-3 F (aq) + HF(g) HF;(ag) K= 2.6 x 10- a. Is fluoride in pH 7.00 drinking water more likely to be present as F"(aq) or HF2 (aq)? O HF2 (aq) O F(aq) b. What is the equilibrium constant for this equilibrium? Number 2 HF(g) + H,0(1) H,0*(aq) + HF, (aq) c. What are the pH and equilibrium concentration of HF2" in a 0.150 M solution of HF? (HF, - Number Number pH = M Check Answer View Solution
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