At -11.5 °C the concentration equilibrium constant K = 9.2 × 10 for a certain reaction. Here are some facts about the reaction: • If the reaction is run at constant pressure, 136. kJ/mol of heat are absorbed. • The initial rate of the reaction is 6.2 mol-L¯¯¹-s¯¯¹. • The net change in moles of gases is -1. Using these facts, can you calculate Kat 1.4 °C? If you said yes, then enter your answer at right. Round it to 2 significant digits. Yes. O No. 0 D

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At -11.5 °C the concentration equilibrium constant K
Here are some facts about the reaction:
• If the reaction is run at constant pressure, 136. kJ/mol of heat are absorbed.
-5
= 9.2 × 10 for a certain reaction.
• The initial rate of the reaction is 6.2 mol L 'S
●
The net change in moles of gases is -1.
Using these facts, can you calculate Kat 1.4 °C?
If you said yes, then enter your answer at right. Round it to
2 significant digits.
If you said no, can you at least decide whether K at
1.4 °C will be bigger or smaller than Kat -11.5 °C?
Yes.
O No.
7
Yes, and K will be
bigger.
Yes, and K will be
smaller.
C
No.
x10
X
Ś
Transcribed Image Text:At -11.5 °C the concentration equilibrium constant K Here are some facts about the reaction: • If the reaction is run at constant pressure, 136. kJ/mol of heat are absorbed. -5 = 9.2 × 10 for a certain reaction. • The initial rate of the reaction is 6.2 mol L 'S ● The net change in moles of gases is -1. Using these facts, can you calculate Kat 1.4 °C? If you said yes, then enter your answer at right. Round it to 2 significant digits. If you said no, can you at least decide whether K at 1.4 °C will be bigger or smaller than Kat -11.5 °C? Yes. O No. 7 Yes, and K will be bigger. Yes, and K will be smaller. C No. x10 X Ś
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