At -5.21 °C the concentration equilibrium constant K = 2.9 × 105 for a certain reaction. с Here are some facts about the reaction: • The net change in moles of gases is -1. • Some of the reactants are liquids and solids. • If the reaction is run at constant pressure, 58.0 kJ/mol of heat are released. Using these facts, can you calculate Kat 16. °C? If you said yes, then enter your answer at right. Round it to 2 significant digits. If you said no, can you at least decide whether Kat 16. °℃ will be bigger or smaller than Kat -5.21 °C? Yes. No. C Yes, and K will be bigger. Yes, and K will be smaller. No.

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At -5.21 °C the concentration equilibrium constant K = 2.9 × 10³ for a certain reaction.
Here are some facts about the reaction:
• The net change in moles of gases is -1.
Some of the reactants are liquids and solids.
• If the reaction is run at constant pressure, 58.0 kJ/mol of heat are released.
●
Using these facts, can you calculate Kat 16. °C?
If you said yes, then enter your answer at right. Round it to
2 significant digits.
If you said no, can you at least decide whether Kat
16. °℃ will be bigger or smaller than Kat -5.21 °C?
Yes.
No.
0
Yes, and K will be
bigger.
Yes, and K will be
smaller.
No.
Transcribed Image Text:At -5.21 °C the concentration equilibrium constant K = 2.9 × 10³ for a certain reaction. Here are some facts about the reaction: • The net change in moles of gases is -1. Some of the reactants are liquids and solids. • If the reaction is run at constant pressure, 58.0 kJ/mol of heat are released. ● Using these facts, can you calculate Kat 16. °C? If you said yes, then enter your answer at right. Round it to 2 significant digits. If you said no, can you at least decide whether Kat 16. °℃ will be bigger or smaller than Kat -5.21 °C? Yes. No. 0 Yes, and K will be bigger. Yes, and K will be smaller. No.
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