We compare the values of Q and K to predict the direction in which a reaction will proceed toward equilibrium. Qc < Kc then: Qc > Kc then Qc = Kc then more reactant forms; more products form; there is no net change more products form; more reactant forms; there is no net change there is no net change; more reactant forms; more products form O more products form; there is no net change; more reactant forms

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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We compare the values of Q and K to predict the direction in which a
reaction will proceed toward equilibrium. Qc < Kc then; Qc > Kc then
Qc = Kc then
more reactant forms; more products form; there is no net change
more products form; more reactant forms; there is no net change
there is no net change; more reactant forms; more products form
O more products form; there is no net change; more reactant forms
Transcribed Image Text:We compare the values of Q and K to predict the direction in which a reaction will proceed toward equilibrium. Qc < Kc then; Qc > Kc then Qc = Kc then more reactant forms; more products form; there is no net change more products form; more reactant forms; there is no net change there is no net change; more reactant forms; more products form O more products form; there is no net change; more reactant forms
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