**Problem Statement:**Assuming the population has an approximate normal distribution, if a sample size \( n = 29 \) has a sample mean \( \bar{x} = 50 \) with a sample standard deviation \( s = 5 \), find the margin of error at a 98% confidence level. *Round the answer to two decimal places.***Solution Process:**1. **Identify Known Values:** - Sample size (\( n \)): 29 - Sample mean (\( \bar{x} \)): 50 - Sample standard deviation (\( s \)): 5 - Confidence level: 98%2. **Identify the Appropriate Statistic:** - Since the standard deviation is known and the sample size is less than 30, use the *t-distribution*. - Calculate the number of degrees of freedom (\( df \)): \( n - 1 = 28 \).3. **Find the Critical t-value (\( t^* \)) for the Desired Confidence Level:** - Use a t-table or statistical software to find \( t^* \) for 98% confidence and 28 degrees of freedom.4. **Calculate the Margin of Error (ME):** - Formula: \( ME = t^* \times \left( \frac{s}{\sqrt{n}} \right) \)5. **Round the Margin of Error:** - Round your calculated margin of error to two decimal places.**Graphs/Diagrams:**- There are no graphs or diagrams in this problem. This explanation will guide students in understanding how to approach and solve the problem of finding a margin of error using information from a sample dataset.

Ans - Given, sample size n = 29 , sample mean = x = 50 A sample standard deviation = s =…

Answered: Assuming the population has an…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

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Problem 1P

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Assuming the population has an approximate normal distribution, if a sample size n = 29 nas a sample mean ī = 50 with a sample standard deviation s = 5, find the margin of error at a 98% confidence level. Round the answer to two decimal places.