Private Four-Year Colleges From the data in CollegeScores4yr we know that about 62% of four-year colleges in the US are private institutions. Suppose that we select samples of n = 75 schools at a time from the population of all four-year colleges and find the proportion of private schools in each sample. (a) Consider the distribution of these sample proportions when n = 75 and p = 0.62. What is its form? Center = i Standard error = i (round to three decimal places) (b) What proportion of these samples will have less than 50% private schools? Round to three decimal places.

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Private Four-Year Colleges From the data in CollegeScores4yr we know that about 62% of four-year colleges in the US are private
institutions. Suppose that we select samples of n = 75 schools at a time from the population of all four-year colleges and find the
proportion of private schools in each sample.
(a) Consider the distribution of these sample proportions when n = 75 and p = 0.62.
What is its form?
Center = i
Standard error =
(round to three decimal places)
(b) What proportion of these samples will have less than 50% private schools? Round to three decimal places.
i
Transcribed Image Text:Private Four-Year Colleges From the data in CollegeScores4yr we know that about 62% of four-year colleges in the US are private institutions. Suppose that we select samples of n = 75 schools at a time from the population of all four-year colleges and find the proportion of private schools in each sample. (a) Consider the distribution of these sample proportions when n = 75 and p = 0.62. What is its form? Center = i Standard error = (round to three decimal places) (b) What proportion of these samples will have less than 50% private schools? Round to three decimal places. i
Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point
estimate for p, the margin of error, and the confidence interval. Assume the results come from a random sample.
A 90% confidence interval for p given that p = 0.7 and n = 120.
Round your answer for the point estimate to two decimal places, and your answers for the margin of error and the confidence interval
to three decimal places.
Point estimate =
Margin of error = + i
The 90% confidence interval is i
to
Transcribed Image Text:Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p, the margin of error, and the confidence interval. Assume the results come from a random sample. A 90% confidence interval for p given that p = 0.7 and n = 120. Round your answer for the point estimate to two decimal places, and your answers for the margin of error and the confidence interval to three decimal places. Point estimate = Margin of error = + i The 90% confidence interval is i to
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