Question 5. You take a simple random sample of n = 49 individuals from this population and calculate the mean cholesterol of the sample. Describe the sampling distribution of .The sampling distribution of is N(190, 40)The sampling distribution o fis N(190, 5.714)The sampling distribution of is N(190, 49)The sampling distribution of is N(190, 7)Question 6. Regarding the mean derived from a sample of n = 49, what is the probability of getting a sample mean that is less than 180? [Determine Pr( ≤ 180).]0.040.400.600.96Question 4. What is the probability of selecting someone at random from this population who has a cholesterol value that is less than 180? 0.250.400.600.80

Sampling Distribution of a Normal Variable : Given a random variable X. Suppose that the population distribution of X is known to be normal, with mean µ andvariance σ2 , that is, X ~ N(µ, σ). Then, for any sample size n, it follows that the sampling distribution of X is normal,with mean µ and variance σ2 / n , that is, X¯ ~ Normal μ,σn Given , random sample size = 49 . Sampling distribution of is N(190, 40) . The following information about the mean and standard deviation has been provided: \mu = 190, \text{ } \sigma = 7, \text{ } n = 49μ=190, σ=7, n=49 We need to compute Pr ( X¯≤180 ). The corresponding z-value needed to be computed : Therefore , Probability of getting a sample mean that is less than 180 = 0.04 The following information has been provided: \mu = 190, \text{ } \sigma = 40μ=190, σ=40 We need to compute \Pr(X \leq 180)Pr(X≤180). The corresponding z-value needed to be computed: Therefore , Probability of selecting someone at random from this population who has a cholesterol value that is less than 180 = 0.040

Answered: Question 5. You take a simple random…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

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Question 5. You take a simple random sample of n = 49 individuals from this population and calculate the mean cholesterol of the sample. Describe the sampling distribution of .

The sampling distribution of is N(190, 40)
The sampling distribution o fis N(190, 5.714)
The sampling distribution of is N(190, 49)
The sampling distribution of is N(190, 7)

Question 6. Regarding the mean derived from a sample of n = 49, what is the probability of getting a sample mean that is less than 180? [Determine Pr( ≤ 180).]

0.04
0.40
0.60
0.96

Question 4. What is the probability of selecting someone at random from this population who has a cholesterol value that is less than 180?

0.25
0.40
0.60
0.80

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

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