Assume that the standard free energy of ATP hydrolysis is -31 kJ/mol. Assume the following values for the standard free energy changes of the four reactions: HK -16.7 kJ/mol; PFK -14.2 kJ/mol; PGK -18.9 kJ/mol; PK -31.7 kJ/mol. (from bio.libretexts.org). Use these values to compute the standard free energy of hydrolysis (releasing Pi) of i. glucose 6-P ii. fructose 1,6-bis-P iii. 1,3-bisphosphoglycerate iv. phosphoenolpyruvate Part b: Which of these four compounds is the strongest phosphoryl donor?______________ Which is the weakest?__________________ Part c: The phosphoglycerate kinase reaction is favorable by -18.9 kJ/mol in the glycolytic direction, as stated above. In gluconeogenesis, this step is simply reversed; i.e. it is not one of the three steps in gluconeogenesis that is driven by using different chemistry than that of glycolysis. How can this be? (Be specific: what specific factors could enable reversal of this step?)
Assume that the standard free energy of ATP hydrolysis is -31 kJ/mol. Assume the following values for the standard free energy changes of the four reactions: HK -16.7 kJ/mol; PFK -14.2 kJ/mol; PGK -18.9 kJ/mol; PK -31.7 kJ/mol. (from bio.libretexts.org). Use these values to compute the standard free energy of hydrolysis (releasing Pi) of i. glucose 6-P ii. fructose 1,6-bis-P iii. 1,3-bisphosphoglycerate iv. phosphoenolpyruvate Part b: Which of these four compounds is the strongest phosphoryl donor?______________ Which is the weakest?__________________ Part c: The phosphoglycerate kinase reaction is favorable by -18.9 kJ/mol in the glycolytic direction, as stated above. In gluconeogenesis, this step is simply reversed; i.e. it is not one of the three steps in gluconeogenesis that is driven by using different chemistry than that of glycolysis. How can this be? (Be specific: what specific factors could enable reversal of this step?)
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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Question 1:
Part a:
Assume that the standard free energy of ATP hydrolysis is -31 kJ/mol. Assume the following values for the standard free energy changes of the four reactions: HK -16.7 kJ/mol; PFK -14.2 kJ/mol; PGK -18.9 kJ/mol; PK -31.7 kJ/mol. (from bio.libretexts.org).
Use these values to compute the standard free energy of hydrolysis (releasing Pi) of
i. glucose 6-P
ii. fructose 1,6-bis-P
iii. 1,3-bisphosphoglycerate
iv. phosphoenolpyruvate
Part b:
Which of these four compounds is the strongest phosphoryl donor?______________ Which is the weakest?__________________
Part c:
The phosphoglycerate kinase reaction is favorable by -18.9 kJ/mol in the glycolytic direction, as stated above.
In gluconeogenesis, this step is simply reversed; i.e. it is not one of the three steps in gluconeogenesis that is driven by using different chemistry than that of glycolysis.
How can this be? (Be specific: what specific factors could enable reversal of this step?)
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Step 1: Free energy change is additive and its sign changes upon reversal of reaction
VIEWStep 2: (a) Calculating standard free energy of hydrolysis of some glycolytic intermediates
VIEWStep 3: (b) Identifying the strongest and weakest phosphoryl donor
VIEWStep 4: (c) How PGK reaction runs in opposite direction during gluconeogenesis
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