Homework Help is Here – Start Your Trial Now!
Science
Advanced Physics
AS. x = 35m acceleration in & direction = 0 + ax=0 acceleration in y & ay = -9.8m/s² Also initial velocity was totally in x direction Thus, 2 y = 0x t + 1/2 ayt ² -22m = 1/2 (-9-80) +² |t = २.|२९ NOW in x direction, direction=-g चे x = ut + 1ax +² x = ut +0 35 = 4(2.128) U = 35 2.12 u = 16.51 m/s 22m Answer PLEASE EXPLAIN THE SOLUTION PROVIDED ABOVE ·35m Î

AS. x = 35m acceleration in & direction = 0 + ax=0 acceleration in y & ay = -9.8m/s² Also initial velocity was totally in x direction Thus, 2 y = 0x t + 1/2 ayt ² -22m = 1/2 (-9-80) +² |t = २.|२९ NOW in x direction, direction=-g चे x = ut + 1ax +² x = ut +0 35 = 4(2.128) U = 35 2.12 u = 16.51 m/s 22m Answer PLEASE EXPLAIN THE SOLUTION PROVIDED ABOVE ·35m Î

icon
Related questions
Question
100%

I NEED AN EXPLANATION DETAIL BY DETAIL PLEASE
I WILL UPVOTE

PLEASE SKIP IF YOU ALREADY DID THIS

AS, x = 35m acceleration in x direction = 0 + ax=0 acceleration in y direction=-g |t = 2.12 s Now in x direction, ⇒ ay = -9.8m/s² Also initial velocity was totally in x direction Thus, y= oxt+f ayta -22m = (-9.80) t u= x = ut + 1 9xf² x = ut + 0 35 = 4(2.128) 35 2.12 u = 16.51 m/s 22m Answer £g PLEASE EXPLAIN THE SOLUTION PROVIDED ABOVE -35m y
Transcribed Image Text:AS, x = 35m acceleration in x direction = 0 + ax=0 acceleration in y direction=-g |t = 2.12 s Now in x direction, ⇒ ay = -9.8m/s² Also initial velocity was totally in x direction Thus, y= oxt+f ayta -22m = (-9.80) t u= x = ut + 1 9xf² x = ut + 0 35 = 4(2.128) 35 2.12 u = 16.51 m/s 22m Answer £g PLEASE EXPLAIN THE SOLUTION PROVIDED ABOVE -35m y
Expert Solution
steps

Step by step

Solved in 2 steps with 1 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer