AR a - 4CDU-AD, 4CBa How many grams of AD, IsMW-285.72 g/mol would be made from the reaction of 2.18E24 molecules of CD la q) (MW-295.97 g/mol), assuming excess AB la q) 1279.92 g/mol0? (given Avogadro's number-6.022E23) Your Answer Answer units Solution Question 29 It is observed that 33.90 g of NaCI (MW 58.44 g/mol) dissolves in 100.0 mL of water at 50 degrees celsius. What is the molarity of NaCl in the solution? Assume that the volume of the solution does not change as the NaCl is added.

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ARa - 4CDU-AD, 6 4Coa
How many grams of AD, IsMW-285.72 g/mol would be made from the reaction
of 2.18E24 molecules of CD la q) (MW-295.97 g/mol), assuming excess AB la g)
1279.92 g/mol)? (given Avogadro's number 6.022E23)
Your Answer
Answer
units
Solution
Question 29
It is observed that 33.90 g of NaCI (MW 58.44 g/mol) dissolves in 100.0 mL of
water at 50 degrees celsius. What is the molarity of NaCl in the solution? Assume
that the volume of the solution does not change as the NaCl is added.
Your Answer:
Transcribed Image Text:ARa - 4CDU-AD, 6 4Coa How many grams of AD, IsMW-285.72 g/mol would be made from the reaction of 2.18E24 molecules of CD la q) (MW-295.97 g/mol), assuming excess AB la g) 1279.92 g/mol)? (given Avogadro's number 6.022E23) Your Answer Answer units Solution Question 29 It is observed that 33.90 g of NaCI (MW 58.44 g/mol) dissolves in 100.0 mL of water at 50 degrees celsius. What is the molarity of NaCl in the solution? Assume that the volume of the solution does not change as the NaCl is added. Your Answer:
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