Name Mass Formula Mass moles Draw Calculations T Read aloud 1200g Ba(OH)₂ + 2Na₂SO4 → BaSO+2NaOH Ask Copilo 171.34 g/mol 2500g 142.04 g/mol 233.39 g/mol 40.00 g/mol

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Using the following image with the respective given. What is the limiting reactant in this equation? With work.
### Chemical Reaction Transcription:

**Reaction:**

\[ \text{Ba(OH)}_2 + 2\text{Na}_2\text{SO}_4 \rightarrow \text{BaSO}_4 + 2\text{NaOH} \]

**Reactants:**

1. **Ba(OH)₂**

   - **Mass:** 1200 g
   - **Formula Mass:** 171.34 g/mol
   - **Moles:** ______

2. **Na₂SO₄**

   - **Mass:** 2500 g
   - **Formula Mass:** 142.04 g/mol
   - **Moles:** ______

**Products:**

1. **BaSO₄**

   - **Mass:** ______
   - **Formula Mass:** 233.39 g/mol
   - **Moles:** ______

2. **NaOH**

   - **Mass:** ______
   - **Formula Mass:** 40.00 g/mol
   - **Moles:** ______

**Calculations:**

- Determine moles of each substance based on given mass and formula mass.
- Verify stoichiometric relationships in the reaction.
Transcribed Image Text:### Chemical Reaction Transcription: **Reaction:** \[ \text{Ba(OH)}_2 + 2\text{Na}_2\text{SO}_4 \rightarrow \text{BaSO}_4 + 2\text{NaOH} \] **Reactants:** 1. **Ba(OH)₂** - **Mass:** 1200 g - **Formula Mass:** 171.34 g/mol - **Moles:** ______ 2. **Na₂SO₄** - **Mass:** 2500 g - **Formula Mass:** 142.04 g/mol - **Moles:** ______ **Products:** 1. **BaSO₄** - **Mass:** ______ - **Formula Mass:** 233.39 g/mol - **Moles:** ______ 2. **NaOH** - **Mass:** ______ - **Formula Mass:** 40.00 g/mol - **Moles:** ______ **Calculations:** - Determine moles of each substance based on given mass and formula mass. - Verify stoichiometric relationships in the reaction.
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