Using the following image. How many grams of Na2SO4 were consumed and not consumed in the reaction? NameMassFormula MassmolesDrawCalculationsT Read aloud1200gBa(OH)₂ + 2Na₂SO4 → BaSO+2NaOHAsk Copilo171.34 g/mol2500g142.04 g/mol233.39 g/mol40.00 g/mol

The given chemical reaction is Mass of Ba(OH)2 = 1200 g Molar mass of Ba(OH)2 = 171.34 g/mol Mass of Na2SO4 = 2500 g Molar mass of Na2SO4 = 142.04 g/mol Molar mass of BaSO4 = 233.39 g/mol Molar mass of NaOH = 40.00 g/mol Mass Na2SO4 consumed and left in the reaction =? ----------------------------------The balanced chemical reaction between Ba(OH)2 and Na2SO4 is ...................(A) ----------------------------------The balanced chemical reaction (A) we have, 1 mol Ba(OH)2 = 1 mol Na2SO4 i.e. 171.34 g Ba(OH)2 = 142.04 g Na2SO4 Therefore, 1200 g Ba(OH)2 = = 995 g Na2SO4 i.e. for 1200 g Ba(OH)2 we need 995 g Na2SO4 but, we have, 2500 g Na2SO4 i.e. Na2SO4 is in excess. Hence, Ba(OH)2 is limiting reactant. ----------------------------------Since, 1200 g Ba(OH)2 reacts with 995 g Na2SO4 Thus, mass of Na2SO4 consumed in the reaction is 995 g And Mass of Na2SO4 left in the reaction is given by i.e. ----------------------------------Mass Na2SO4 consumed in the reaction = 995 g Mass Na2SO4 left in the reaction = 1505 g ******************************