Apply the loop rule to loop abcdefghija in the figure below. E, = 24.0 V b d 0.10 2 R, 5.0 2 Rs 20 2 E2 = 48.0 V R2 a 0.50 2 40 Ω 0.20 2 R3 78 2 E4 36.0 V E3 6.0 V r3 1 0.05 Ω h -(1,R2) + E, - (1,r2) – (1,R4) – (I3r2) – E4 – (13r3) + E4 – (I,R3) = 0 O -(1,R,) + E, - (I,r2) – (1,R2) – (I33) – E4 - (13r3) + E4 - (1,R4) = 0 O -(1,R,) + E, - (I,r,) – (1,R5) – (I3ľa) – E4 – (I3r3) + Ez - (I,R3) = 0 O -(I,R2) + E, - (I3r3) – (I„R5) – (I3r4) – E, - (I3r3) + E4 - (I,R4) = 0 Additional Materials Reading

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Chapter1: Units, Trigonometry. And Vectors
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Apply the loop rule to loop abcdefghija in the figure below.
E, = 24.0 V
b
d
0.10 2
R
5.0 2
Rs
20 2
E2 = 48.0 V
R2
k
12
a
e
0.50 2
40 2
0.20 2
R3
78 2
1s E3
E4 = 36.0 V
6.0 V
%3D
1 0.05 Ωh
O -(1,R2) + E, - (I,r2) – (1,R4) – (I3r2) - E4 – (1gr3) + E4 - (1,R3) = 0
O -(1,R1) + E, - (I,r2) – (1,R,) – (I3r3) – E, - (I,r3) + E - (I,R4) = 0
-(1,R;) + E, - (1,i) - (1,R5) – (I3r4) - E, - (13r3) + Ez - (I3R3) = 0
O -(1,R2) + E, - (I3r3) – (I„R5) – (I34) – E4 - (I3r3) + E4 - (I3R4) = 0
Additional Materials
O Reading
Transcribed Image Text:Apply the loop rule to loop abcdefghija in the figure below. E, = 24.0 V b d 0.10 2 R 5.0 2 Rs 20 2 E2 = 48.0 V R2 k 12 a e 0.50 2 40 2 0.20 2 R3 78 2 1s E3 E4 = 36.0 V 6.0 V %3D 1 0.05 Ωh O -(1,R2) + E, - (I,r2) – (1,R4) – (I3r2) - E4 – (1gr3) + E4 - (1,R3) = 0 O -(1,R1) + E, - (I,r2) – (1,R,) – (I3r3) – E, - (I,r3) + E - (I,R4) = 0 -(1,R;) + E, - (1,i) - (1,R5) – (I3r4) - E, - (13r3) + Ez - (I3R3) = 0 O -(1,R2) + E, - (I3r3) – (I„R5) – (I34) – E4 - (I3r3) + E4 - (I3R4) = 0 Additional Materials O Reading
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