What equation do you get when you appry Kirchhofes junction ruse at point a? I3= R₁ 5.02 E₁ = 24.0 V 4/% 0.10 Ω E2 = 48.0 V R₂ ww e 0.50 Ω 40 Ω R • 20 Ω R 78 Ω E3=6.0 V i 0.05 h TA 0.20 Ω 2012 E=36.0 V

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