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For each of the circuits below what is the current through each resistor? (a) (b) (c) ww R1 50 Ω BAT1 9 V BAT1 12 V ww www R1 50 Ω ww R2 70 Ω R2 70 Ω ww R3 100 Ω 400 BAT2 17 V (d) wwwww R2 70 2 R1 50 22 #00 BAT1 12 V R1 50 Ω www w R3 100 Ω R3 100 22 R2 70 Ω +1+ +10+ BAT1 BAT2 12 V 17 V

For each of the circuits below what is the current through each resistor? (a) (b) (c) ww R1 50 Ω BAT1 9 V BAT1 12 V ww www R1 50 Ω ww R2 70 Ω R2 70 Ω ww R3 100 Ω 400 BAT2 17 V (d) wwwww R2 70 2 R1 50 22 #00 BAT1 12 V R1 50 Ω www w R3 100 Ω R3 100 22 R2 70 Ω +1+ +10+ BAT1 BAT2 12 V 17 V

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### Circuit Analysis: Determining Current Through Resistors Below are four different electrical circuit diagrams. For each circuit, we'll determine the current through each resistor. #### Diagram (a) - **Components:** - Resistor R1: 50 Ω - Resistor R2: 70 Ω - Battery BAT1: 9 V - **Configuration:** Series circuit with R1 and R2 connected in series with BAT1. #### Diagram (b) - **Components:** - Resistor R1: 50 Ω - Resistor R2: 70 Ω - Resistor R3: 100 Ω - Battery BAT1: 12 V - **Configuration:** Series circuit with R1, R2, and R3 connected in series with BAT1. #### Diagram (c) - **Components:** - Resistor R1: 50 Ω - Resistor R2: 70 Ω - Resistor R3: 100 Ω - Batteries: BAT1 (12 V) and BAT2 (17 V) in series - **Configuration:** Series circuit with R1, R2, R3. The total voltage is the sum of BAT1 and BAT2 (29 V). #### Diagram (d) - **Components:** - Resistor R1: 50 Ω - Resistor R2: 70 Ω - Resistor R3: 100 Ω - Batteries: BAT1 (12 V) and BAT2 (17 V) in series - **Configuration:** Series circuit with R1, R2, and R3. The total voltage from BAT1 and BAT2 is 29 V. ### Analyzing the Circuits In all diagrams, the resistors are connected in series. The total current (I) through each resistor can be calculated using Ohm's Law: \[ I = \frac{V}{R_{\text{total}}} \] Where: - \( V \) is the total voltage supplied by the battery (or batteries). - \( R_{\text{total}} \) is the sum of the resistances in the circuit. For calculation: - **Diagram (a):** \( R_{\text{total}} = 50 \, \Omega + 70 \, \Omega = 120 \, \Omega \) - **Diagram (b):
Transcribed Image Text:### Circuit Analysis: Determining Current Through Resistors Below are four different electrical circuit diagrams. For each circuit, we'll determine the current through each resistor. #### Diagram (a) - **Components:** - Resistor R1: 50 Ω - Resistor R2: 70 Ω - Battery BAT1: 9 V - **Configuration:** Series circuit with R1 and R2 connected in series with BAT1. #### Diagram (b) - **Components:** - Resistor R1: 50 Ω - Resistor R2: 70 Ω - Resistor R3: 100 Ω - Battery BAT1: 12 V - **Configuration:** Series circuit with R1, R2, and R3 connected in series with BAT1. #### Diagram (c) - **Components:** - Resistor R1: 50 Ω - Resistor R2: 70 Ω - Resistor R3: 100 Ω - Batteries: BAT1 (12 V) and BAT2 (17 V) in series - **Configuration:** Series circuit with R1, R2, R3. The total voltage is the sum of BAT1 and BAT2 (29 V). #### Diagram (d) - **Components:** - Resistor R1: 50 Ω - Resistor R2: 70 Ω - Resistor R3: 100 Ω - Batteries: BAT1 (12 V) and BAT2 (17 V) in series - **Configuration:** Series circuit with R1, R2, and R3. The total voltage from BAT1 and BAT2 is 29 V. ### Analyzing the Circuits In all diagrams, the resistors are connected in series. The total current (I) through each resistor can be calculated using Ohm's Law: \[ I = \frac{V}{R_{\text{total}}} \] Where: - \( V \) is the total voltage supplied by the battery (or batteries). - \( R_{\text{total}} \) is the sum of the resistances in the circuit. For calculation: - **Diagram (a):** \( R_{\text{total}} = 50 \, \Omega + 70 \, \Omega = 120 \, \Omega \) - **Diagram (b):
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