(a) (c) R1 60 Ω R1 100 Ω ww R2 50 Ω R4 80 Ω www BAT1 9 V Μ Μ Hilt 12 V ww R3 80 Ω R5 150 Ω ww R2 120 Ω BAT2 12 V ww R3 75 Ω (b) R1 100 Ω BAT1 9V R2 120 Ω BAT2 12 V ww R3 75 Ω
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A: C1 = 1 micro farad C2 = 2 micro farad C3 = 3 micro farad
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Q: VSI 1.5 V R₁ 47 02 www www R₂ 10 Ω R3 2702 www IB R₁ 4.7 92 VS2 3 V R₁ 15 Ω www Ic H VS3 1.5 V
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Q: What is the equivalent value of the capacitance for the figure shown? C1 = 16.0 μF, C2 = 23.0 μF and…
A: option (C) 32.4 µF is correct.Explanation:
Current through each resistor.
Given,
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- A circuit is shown in the figure. Which equation is the correct "loop rule" for Loop 1 ? a. +E1 − I1 R1 − I1 R2 − E2 + I3 R3 − I4 R4 = 0b. +E1 − I1 R1 − I1 R2 − E2 − I3 R3 = 0c. +E1 − I1 R1 − I1 R2 − E2 + I3 R3 = 0d. +E1 + I1 R1 + I1 R2 + E2 + I3 R3 = 0e. +E1 − I1 R1 − I1 R2 + E2 − I3 R3 − I4 R4 = 0What is the value of R3 in the figure? R1 = 14.3Ω, R2 = 18.9Ω, ΔV = 7.00 V, I = 7.80A 0.991Ω 0.897Ω 1.01Ω 0.333ΩSix capacitance values are listed below for the capacitors that are connected as shown.C1=C1=5.68μFμFC2=C2=3.35μFμFC3=C3=7.02μFμFC4=C4=2.69μFμFC5=C5=0.45μFμFC6=C6=14.9μF What is the equivalent capacitance, in μF microfarads, of the given six-capacitor combination?
- PLEASE ANSWER ALL PARTS!!!!! VERY URGENT!!!!!!!!!!!!For each of the circuits below what is the current through each resistor? (a) (b) (c) ww R1 50 Ω BAT1 9 V www R1 50 Ω BAT1 12 V пи www R2 70Q2 R2 70 Ω BAT2 17 V R3 100 £2 (d) www www R3 100 Ω R1 50 Ω ww R1 50 Ω R2 70 Ω BAT1 12 V BAT1 12 V wwww R2 70 Ω BAT2 17 V R3 100 Ω +Apply the loop rule to loop abcdefghija in the figure below. E, = 24.0 V b d 0.10 2 R 5.0 2 Rs 20 2 E2 = 48.0 V R2 k 12 a e 0.50 2 40 2 0.20 2 R3 78 2 1s E3 E4 = 36.0 V 6.0 V %3D 1 0.05 Ωh O -(1,R2) + E, - (I,r2) – (1,R4) – (I3r2) - E4 – (1gr3) + E4 - (1,R3) = 0 O -(1,R1) + E, - (I,r2) – (1,R,) – (I3r3) – E, - (I,r3) + E - (I,R4) = 0 -(1,R;) + E, - (1,i) - (1,R5) – (I3r4) - E, - (13r3) + Ez - (I3R3) = 0 O -(1,R2) + E, - (I3r3) – (I„R5) – (I34) – E4 - (I3r3) + E4 - (I3R4) = 0 Additional Materials O Reading