alA A Aa-AE E AL Tv12AaBbCcDc AaBbCcDc AaBbC AaBbCcl AaB AaBbCcC AaBbCcDI U - abx, x' Ae- A-三三=1 Normal I No Spac. Heading 1 Heading 2TitleSubtitleSubtle Em.FontParagraphStylesVariables Entered/RemovedVariablesVariablesHodelEnteredRenovedMethod1Entera. Dependent Variable: Yb. All requested variables entered.Model SumenaryStd. ErrorAdjusted Rof theEstimateModelRR SquareSquare.810-6576004.52136a. Predictors: (Constant), IANOVASum ofModelSquares234.844122.656dfMean SquareRegressionResidualSig..015234.84411.4886.20.443Total357.500a. Dependent Variable: yb. Predictors: (Constant), ICoefficientsUnstandardizedCoefficientsStandardizedCoefficientsBetaModelBTStd. Error(Constant)76.960-4.495Sig..00010.0737.6407.6401.326-.810-3.389.015a. Dependent Variable:Y耳searcha 3. Assume that a researcher is interested in the relationship between hours of sleepand anxiety. Eight individuals are randomly selected and the amount of hours sleptand anxiety scores are measured. The scores are reported in the following table.Hours of sleep (x)Anxiety score (y)5.5556478457.25508.535398.753936Answer the following questions using the SPSS regression analysis OUTPUT(given below):a. From the SPSS regression analysis OUTPUT (given below), write theestimated regression line of anxiety score (y) based on hours of sleep (x).b. Does amount of sleep (x) significantly predicts the anxiety score (y), using a=0.05? State your null and alternative hypotheses.C. What is the predicted anxiety score (y) for someone who sleeps for 5 hours(x)D FocusNa(?

3. a. From the SPSS output, the intercept is 76.960, and the slope is -4.495. The estimated regression line of anxiety score (y) based on hours of sleep (x) is, y^=a+bx=76.960-4.495x Thus, the estimated regression line of anxiety score (y) based on hours of sleep (x) is y^=76.960-4.495x. b. The hypothesis is, Null hypothesis: H0:β1=0 Alternative hypothesis: Ha:β1≠0 From the SPSS output, the test statistic for slope is -3.389, and corresponding p-value is 0.015. Decision rule: If p-value≤α, then reject the null hypothesis. Otherwise, do not reject the null hypothesis. Conclusion: The p-value (0.015) is less than the level of significance (0.05). Based on decision rule, reject the null hypothesis. Thus, it can be concluded that the amount of sleep (x) significantly predicts the anxiety scores (y).c. The predicted anxiety score (y) for someone who sleeps for 5 hours (x) is, y^=76.960-4.4955=76.960-22.475=54.485 Thus, the predicted anxiety score (y) for someone who sleeps for 5 hours (x) is 54.485.

Math

Statistics

Answer the following questions using the SPSS regression analysis OUTPUT (given below): a. From the SPSS regression analysis OUTPUT (given below), write the estimated regression line of anxiety score (y) based on hours of sleep (x). b. Does amount of sleep (x) significantly predicts the anxiety score (y), using a= 0.05? State your null and alternative hypotheses. c. What is the predicted anxiety score (y) for someone who sleeps for 5 hours (x)

Answer the following questions using the SPSS regression analysis OUTPUT (given below): a. From the SPSS regression analysis OUTPUT (given below), write the estimated regression line of anxiety score (y) based on hours of sleep (x). b. Does amount of sleep (x) significantly predicts the anxiety score (y), using a= 0.05? State your null and alternative hypotheses. c. What is the predicted anxiety score (y) for someone who sleeps for 5 hours (x)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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