Analyze the free-body diagram, given the coefficients of static and kinetic friction. Determine whether the block will slide and the net force on the system. static kinetic friction is not shown, but must be included in calculations Hs = 0.25 Hk = 0.2 fs,max= 50 %3D fk = 40 W2 [N] slide? friction [N] friction |Fnel [N] direction 102N 22 yes, down-rigt 40 40 up-left W2 W 200N 50 up-left v (see table) 80 no W 225N 50 down-righ no 120 18 40 down-righ v 58 righ cannot
Analyze the free-body diagram, given the coefficients of static and kinetic friction. Determine whether the block will slide and the net force on the system. static kinetic friction is not shown, but must be included in calculations Hs = 0.25 Hk = 0.2 fs,max= 50 %3D fk = 40 W2 [N] slide? friction [N] friction |Fnel [N] direction 102N 22 yes, down-rigt 40 40 up-left W2 W 200N 50 up-left v (see table) 80 no W 225N 50 down-righ no 120 18 40 down-righ v 58 righ cannot
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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Problem 1.1MA
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![Analyze the free-body diagram, given the coefficients of static and kinetic friction.
Determine whether the block will slide and the net force on the system.
static
kinetic
Hs = 0.25
friction is not shown, but must be incuded in calculations
Hk = 0.2
fs,max =
50
%3D
fr =
W2 [N]
slide?
friction [N]
friction
direction
| Fnel [N]
40
yes, down-righ
40
up-left v
22
W.-102
W2
W = 200N
50
up-left v
(see table)
80
no
W = 225N
50
down-righ
no
120
18
40
down-righ
160
yes, up-left v
58
40
down-righ v
yes, up-left
annot be de
200
check answers](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F18e5c811-cff1-48b8-a936-4c74d4925c39%2F41f8f1ec-ee59-4a6d-883f-b7de12fa5098%2Fqduljw_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Analyze the free-body diagram, given the coefficients of static and kinetic friction.
Determine whether the block will slide and the net force on the system.
static
kinetic
Hs = 0.25
friction is not shown, but must be incuded in calculations
Hk = 0.2
fs,max =
50
%3D
fr =
W2 [N]
slide?
friction [N]
friction
direction
| Fnel [N]
40
yes, down-righ
40
up-left v
22
W.-102
W2
W = 200N
50
up-left v
(see table)
80
no
W = 225N
50
down-righ
no
120
18
40
down-righ
160
yes, up-left v
58
40
down-righ v
yes, up-left
annot be de
200
check answers
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