Advertised missile performance: Natural Frequency < 0.30 Hz Damping ratio > 0.65 a = Angle of attack [rad] q = pitch rate [rad] Xcg 1.25m center of gravity Zcg = Om center of gravity = The equations of motion for the missile are à = q -0.435sin a + 0.07a -0.00014q q= 111.484(xcg - 1.483)a - (2.2968 - 3.156zcg)q+3.448 + 137895zcg To acquire the target the missile needs to fly at α = 0.017 [rad] q₁ = 0 [rad/s] 8 = 0 [rad] Determine if the missile is stable about the given equilibrium point.
Advertised missile performance: Natural Frequency < 0.30 Hz Damping ratio > 0.65 a = Angle of attack [rad] q = pitch rate [rad] Xcg 1.25m center of gravity Zcg = Om center of gravity = The equations of motion for the missile are à = q -0.435sin a + 0.07a -0.00014q q= 111.484(xcg - 1.483)a - (2.2968 - 3.156zcg)q+3.448 + 137895zcg To acquire the target the missile needs to fly at α = 0.017 [rad] q₁ = 0 [rad/s] 8 = 0 [rad] Determine if the missile is stable about the given equilibrium point.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![汇
Advertised missile performance:
Natural Frequency < 0.30 Hz
Damping ratio > 0.65
a = Angle of attack [rad]
q = pitch rate [rad]
= 1.25m center of gravity
Xcg
Zcg = Om center of gravity
The equations of motion for the missile are
a = q - 0.435sin a + 0.07a -0.00014q
q = 111.484(xcg - 1.483)a - (2.2968 - 3.156zcg)q +3.448 + 137895Zcg
To acquire the target the missile needs to fly at
α = 0.017 [rad] qo= 0 [rad/s] = 0 [rad]
So
Determine if the missile is stable about the given equilibrium point.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb78840cf-991a-43cf-baf3-7d430789620d%2Fb2956af8-2f3d-4db0-825d-cafa2ed0504a%2Fh9zmr2_processed.png&w=3840&q=75)
Transcribed Image Text:汇
Advertised missile performance:
Natural Frequency < 0.30 Hz
Damping ratio > 0.65
a = Angle of attack [rad]
q = pitch rate [rad]
= 1.25m center of gravity
Xcg
Zcg = Om center of gravity
The equations of motion for the missile are
a = q - 0.435sin a + 0.07a -0.00014q
q = 111.484(xcg - 1.483)a - (2.2968 - 3.156zcg)q +3.448 + 137895Zcg
To acquire the target the missile needs to fly at
α = 0.017 [rad] qo= 0 [rad/s] = 0 [rad]
So
Determine if the missile is stable about the given equilibrium point.
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