Problem 22 Determine velocity, normal, tangent, and full acceleration of particle M if block 1 travels distance s.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Problem 22

Determine velocity, normal, tangent, and full acceleration of particle M if block 1 travels distance s. 

Figure 2.22.
1.
2.
MN
3.
Transcribed Image Text:Figure 2.22. 1. 2. MN 3.
Determine velocity, normal, tangent, and full accelerations of particle M if block 1 travels distance s.
Problem
Radii, cm
X = x(t) (x-cm, t-s)
S, m
%23
R2
r2
R3
60
45
36
10 + 1002
0.5
80
60
45
80/2
0.1
100
60
75
18 + 7012
0.2
58
45
60
50f2
0.5
80
45
30
8 + 40t2
0.1
100
60
30
5+ 60f2
0.5
7.
45
35
105
7 + 9012
0.2
35
10
10
4 + 3012
0.5
9.
40
30
15
3 + 80t2
0.2
10
15
40
702
0.4
11
40
25
20
5 + 40f2
0.3
12
20
15
10
2 + 5012
0.1
13
30
20
40
60/2
0.4
14
15
10
15
6 + 2012
0.1
15
15
10
15
8 + 4012
0.3
16
20
15
15
3 + 4012
0.4
17
15
10
20
8012
0.6
18
20
15
10
4 + 2012
0.3
19
15
10
20
5 + 802
0.2
20
25
15
10
502
0.3
21
20
10
30
10
4 + 90f2
0.5
22
40
20
35
10 + 402
0.5
23
40
30
30
15
7 +402
0.6
24
30
15
40
20
902
0.2
25
50
20
60
2 +502
0.5
26
32
16
32
16
5 + 602
0.1
27
40
18
40
18
6 + 302
0.3
28
40
20
40
15
50tr2
0.4
29
25
20
50
25
3 + 302
0.6
30
30
15
20
5 + 602
0.2
3.
1,
23
456 78
Transcribed Image Text:Determine velocity, normal, tangent, and full accelerations of particle M if block 1 travels distance s. Problem Radii, cm X = x(t) (x-cm, t-s) S, m %23 R2 r2 R3 60 45 36 10 + 1002 0.5 80 60 45 80/2 0.1 100 60 75 18 + 7012 0.2 58 45 60 50f2 0.5 80 45 30 8 + 40t2 0.1 100 60 30 5+ 60f2 0.5 7. 45 35 105 7 + 9012 0.2 35 10 10 4 + 3012 0.5 9. 40 30 15 3 + 80t2 0.2 10 15 40 702 0.4 11 40 25 20 5 + 40f2 0.3 12 20 15 10 2 + 5012 0.1 13 30 20 40 60/2 0.4 14 15 10 15 6 + 2012 0.1 15 15 10 15 8 + 4012 0.3 16 20 15 15 3 + 4012 0.4 17 15 10 20 8012 0.6 18 20 15 10 4 + 2012 0.3 19 15 10 20 5 + 802 0.2 20 25 15 10 502 0.3 21 20 10 30 10 4 + 90f2 0.5 22 40 20 35 10 + 402 0.5 23 40 30 30 15 7 +402 0.6 24 30 15 40 20 902 0.2 25 50 20 60 2 +502 0.5 26 32 16 32 16 5 + 602 0.1 27 40 18 40 18 6 + 302 0.3 28 40 20 40 15 50tr2 0.4 29 25 20 50 25 3 + 302 0.6 30 30 15 20 5 + 602 0.2 3. 1, 23 456 78
Expert Solution
Step 1

Given:

The pulley arrangement is shown below:

Mechanical Engineering homework question answer, step 1, image 1

From table,

Radius of the cylinder is 35 cm.

Radius of bigger pulley at 2 is 40 cm.

Radius of smaller pulley at 2 is 20 cm.

Position time relation of the mass is,

x=xtx=10+40t2

Distance travelled by the block is 0.5 m or 50 cm.

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