Problem 22 Determine velocity, normal, tangent, and full acceleration of particle M if block 1 travels distance s.
Problem 22 Determine velocity, normal, tangent, and full acceleration of particle M if block 1 travels distance s.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
Problem 22
Determine velocity, normal, tangent, and full acceleration of particle M if block 1 travels distance s.

Transcribed Image Text:Figure 2.22.
1.
2.
MN
3.

Transcribed Image Text:Determine velocity, normal, tangent, and full accelerations of particle M if block 1 travels distance s.
Problem
Radii, cm
X = x(t) (x-cm, t-s)
S, m
%23
R2
r2
R3
60
45
36
10 + 1002
0.5
80
60
45
80/2
0.1
100
60
75
18 + 7012
0.2
58
45
60
50f2
0.5
80
45
30
8 + 40t2
0.1
100
60
30
5+ 60f2
0.5
7.
45
35
105
7 + 9012
0.2
35
10
10
4 + 3012
0.5
9.
40
30
15
3 + 80t2
0.2
10
15
40
702
0.4
11
40
25
20
5 + 40f2
0.3
12
20
15
10
2 + 5012
0.1
13
30
20
40
60/2
0.4
14
15
10
15
6 + 2012
0.1
15
15
10
15
8 + 4012
0.3
16
20
15
15
3 + 4012
0.4
17
15
10
20
8012
0.6
18
20
15
10
4 + 2012
0.3
19
15
10
20
5 + 802
0.2
20
25
15
10
502
0.3
21
20
10
30
10
4 + 90f2
0.5
22
40
20
35
10 + 402
0.5
23
40
30
30
15
7 +402
0.6
24
30
15
40
20
902
0.2
25
50
20
60
2 +502
0.5
26
32
16
32
16
5 + 602
0.1
27
40
18
40
18
6 + 302
0.3
28
40
20
40
15
50tr2
0.4
29
25
20
50
25
3 + 302
0.6
30
30
15
20
5 + 602
0.2
3.
1,
23
456 78
Expert Solution

Step 1
Given:
The pulley arrangement is shown below:
From table,
Radius of the cylinder is 35 cm.
Radius of bigger pulley at 2 is 40 cm.
Radius of smaller pulley at 2 is 20 cm.
Position time relation of the mass is,
Distance travelled by the block is 0.5 m or 50 cm.
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