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Since the weight of cylinder and friction coefficient are not given, we have assumed some value Matlab code: close all clear all clc W=10; % Enter weight of one cylinder in lb r=5; % Enter radius of cylinder in ft mu_s= 0.3; %Enter static friction coefficient mu_k=0.2; %Enter kinetic friction coefficient a= 10; % Enter acceleration of the cylinder in ft/s2 g=32.17; %Gravity in ft/s2 =0.5*(W/g)*r^2; %Moment of inertial F=(I* (a/r))/r; %Frictinal force using moment equation if(mu_s*W>F) P=W*((a/g)-mu_s); else P=W*((a/g)+mu_k); end Identical cylinders of weight and radiusare pushed by a series of moving arms. The coefficient of friction between all surfaces is . Denoting by the magnitude of the acceleration of the arms, derive an expression for (a) the maximum allowable value of if each cylinder is to roll without sliding, (b) the minimum allowable value of if each cylinder is to move to the right without rotating. Part (c) Let, and between all surfaces. Determine the horizontal component of the force exerted on each cylinder when the acceleration is (1) to the right and (2) 10 to the right. Benchmark solutions for part (c) are given as (1) 1.456 lb to the right, (2) 2.66 lb to the right. For part (c), your solution should be coded into MATLAB so it can easily be run for alternate cases. Part (d) Plot the horizontal component of the force exerted on each cylinder for different ranges of acceleration, which illustrate the various case of rolling and sliding obtained in parts (a) and (b).

Since the weight of cylinder and friction coefficient are not given, we have assumed some value Matlab code: close all clear all clc W=10; % Enter weight of one cylinder in lb r=5; % Enter radius of cylinder in ft mu_s= 0.3; %Enter static friction coefficient mu_k=0.2; %Enter kinetic friction coefficient a= 10; % Enter acceleration of the cylinder in ft/s2 g=32.17; %Gravity in ft/s2 =0.5*(W/g)*r^2; %Moment of inertial F=(I* (a/r))/r; %Frictinal force using moment equation if(mu_s*W>F) P=W*((a/g)-mu_s); else P=W*((a/g)+mu_k); end Identical cylinders of weight and radiusare pushed by a series of moving arms. The coefficient of friction between all surfaces is . Denoting by the magnitude of the acceleration of the arms, derive an expression for (a) the maximum allowable value of if each cylinder is to roll without sliding, (b) the minimum allowable value of if each cylinder is to move to the right without rotating. Part (c) Let, and between all surfaces. Determine the horizontal component of the force exerted on each cylinder when the acceleration is (1) to the right and (2) 10 to the right. Benchmark solutions for part (c) are given as (1) 1.456 lb to the right, (2) 2.66 lb to the right. For part (c), your solution should be coded into MATLAB so it can easily be run for alternate cases. Part (d) Plot the horizontal component of the force exerted on each cylinder for different ranges of acceleration, which illustrate the various case of rolling and sliding obtained in parts (a) and (b).

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Provided is A, B, C. I only need d to finish.
a) FBD of one cylinder Force equation in vertical direction: W = N Frictional force: F = μ_N = μ W Force equation in horizontal direction P+ F = Ma W P = P = W = W ( ²1 – Ps) a F Step3 c) b) Force equation in vertical direction: Force equation in vertical direction: W = N Frictional force: F = ₂N = kW Force equation in horizontal direction P-F = Ma W P = a + F 9 = W ( ² + μk) P = W Step4 d) c) Since the weight of cylinder and friction coefficient are not given, we have assumed some value Matlab code: close all clear all
Transcribed Image Text:a) FBD of one cylinder Force equation in vertical direction: W = N Frictional force: F = μ_N = μ W Force equation in horizontal direction P+ F = Ma W P = P = W = W ( ²1 – Ps) a F Step3 c) b) Force equation in vertical direction: Force equation in vertical direction: W = N Frictional force: F = ₂N = kW Force equation in horizontal direction P-F = Ma W P = a + F 9 = W ( ² + μk) P = W Step4 d) c) Since the weight of cylinder and friction coefficient are not given, we have assumed some value Matlab code: close all clear all
Since the weight of cylinder and friction coefficient are not given, we have assumed some value Matlab code: close all clear all clc W=10; %Enter weight of one cylinder in lb r=5; % Enter radius of cylinder in ft mu_s= 0.3; % Enter static friction coefficient mu_k=0.2; % Enter kinetic friction coefficient a= 10; % Enter acceleration of the cylinder in ft/s2 g=32.17; %Gravity in ft/s2 I=0.5*(W/g)*r^2; nent of inertial F=(I*(a/r))/r; %Frictinal force using moment equation if(mu_s*W>F) P=W*((a/g)-mu_s); else P=W*((a/g)+mu_k); end Identical cylinders of weight and radiusare pushed by a series of moving arms. The coefficient of friction between all surfaces is . Denoting by the magnitude of the acceleration of the arms, derive an expression for (a) the maximum allowable value of if each cylinder is to roll without sliding, (b) the minimum allowable value of if each cylinder is to move to the right without rotating. Part (c) Let, and between all surfaces. Determine the horizontal component of the force exerted on each cylinder when the acceleration is (1) to the right and (2) 10 to the right. Benchmark solutions for part (c) are given as (1) 1.456 lb to the right, (2) 2.66 lb to the right. For part (c), your solution should be coded into MATLAB so it can easily be run for alternate cases. Part (d) Plot the horizontal component of the force exerted on each cylinder for different ranges of acceleration, which illustrate the various case of rolling and sliding obtained in parts (a) and (b).
Transcribed Image Text:Since the weight of cylinder and friction coefficient are not given, we have assumed some value Matlab code: close all clear all clc W=10; %Enter weight of one cylinder in lb r=5; % Enter radius of cylinder in ft mu_s= 0.3; % Enter static friction coefficient mu_k=0.2; % Enter kinetic friction coefficient a= 10; % Enter acceleration of the cylinder in ft/s2 g=32.17; %Gravity in ft/s2 I=0.5*(W/g)*r^2; nent of inertial F=(I*(a/r))/r; %Frictinal force using moment equation if(mu_s*W>F) P=W*((a/g)-mu_s); else P=W*((a/g)+mu_k); end Identical cylinders of weight and radiusare pushed by a series of moving arms. The coefficient of friction between all surfaces is . Denoting by the magnitude of the acceleration of the arms, derive an expression for (a) the maximum allowable value of if each cylinder is to roll without sliding, (b) the minimum allowable value of if each cylinder is to move to the right without rotating. Part (c) Let, and between all surfaces. Determine the horizontal component of the force exerted on each cylinder when the acceleration is (1) to the right and (2) 10 to the right. Benchmark solutions for part (c) are given as (1) 1.456 lb to the right, (2) 2.66 lb to the right. For part (c), your solution should be coded into MATLAB so it can easily be run for alternate cases. Part (d) Plot the horizontal component of the force exerted on each cylinder for different ranges of acceleration, which illustrate the various case of rolling and sliding obtained in parts (a) and (b).
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