Analysis 7 Days 14 Days no. of events/total no. Risk Difference (95% CI) percentage points -1.6 (-4.0 to 0.8) Intention-to-treat Per-protocol 261/1802 286/1779 178/1370 222/1483 -2.0 (-4.5 to 0.6) Modified intention-to-treat 247/1788 272/1765 -1.6 (-3.9 to 0.7) -8.0-6.0-4.0 -2.0 0.0 2.0 4.0 6.0 8.0 7 Days Noninferior 7 Days Inferior

Analysis 7 Days 14 Days no. of events/total no. Risk Difference (95% CI) percentage points -1.6 (-4.0 to 0.8) Intention-to-treat Per-protocol 261/1802 286/1779 178/1370 222/1483 -2.0 (-4.5 to 0.6) Modified intention-to-treat 247/1788 272/1765 -1.6 (-3.9 to 0.7) -8.0-6.0-4.0 -2.0 0.0 2.0 4.0 6.0 8.0 7 Days Noninferior 7 Days Inferior

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter10: Statistics

Section10.1: Measures Of Center

Problem 4GP

See similar textbooks

Similar questions

1. DETAILS PECKSTAT2COREQ 9.R.084.S. MY NOTES In a survey on supernatural experiences, 728 of 4,003 adult Americans surveyed reported that they had seen a ghost. Assume that this sample is representative of the population of adult Americans. (a) Use the given information to estimate the proportion of adult Americans who would say they have seen a ghost. (Round your answer to three decimal places.) (b) Verify that the conditions for use of the margin of error formula to be appropriate are met. Select---v. The condition that the The condition that the sample is a random sample from the population of interest or the sample is selected in a way that should result in a representative sample is sample size is large is ---Select--- v. (c) Calculate the margin of error. (Round your answer to three decimal places.) (d) Interpret the margin of error in context. O It is unlikely that the estimated proportion of all adult Americans who would say they have seen a ghost differs from the true…
A special bumper was installed on selected vehicles in a large fleet. The dollar cost of body repairs was recorded for all vehicles that were involved in accidents over a 1-year period. Those with the special bumper are the test group and the other vehicles are the control group, shown below. Each "repair incident" is defined as an invoice (which might include more than one separate type of damage). Statistic Test Group Control Group Mean Damage X¯¯¯1X¯1 = $ 1,077 X¯¯¯2X¯2 = $ 1,800 Sample Std. Dev. s1 = $ 693 s2 = $ 814 Repair Incidents n1 = 16 n2 = 13 Source: Unpublished study by Thomas W. Lauer and Floyd G. Willoughby. (a) Construct a 90 percent confidence interval for the true difference of the means assuming equal variances. (Round your final answers to 3 decimal places. Negative values should be indicated by a minus sign.) The 90% confidence interval is from to (b) Repeat part (a), using the assumption of unequal variances with Welch's…
A special bumper was installed on selected vehicles in a large fleet. The dollar cost of body repairs was recorded for all vehicles that were involved in accidents over a 1-year period. Those with the special bumper are the test group and the other vehicles are the control group, shown below. Each "repair incident" is defined as an invoice (which might include more than one separate type of damage). Statistic Test Group Control Group Mean Damage X¯¯¯1X¯1 = $ 1,153 X¯¯¯2X¯2 = $ 1,751 Sample Std. Dev. s1 = $ 663 s2 = $ 820 Repair Incidents n1 = 16 n2 = 14 Source: Unpublished study by Thomas W. Lauer and Floyd G. Willoughby. (a) Construct a 99 percent confidence interval for the true difference of the means assuming equal variances. (Round your final answers to 3 decimal places. Negative values should be indicated by a minus sign.) The 99% confidence interval is from to (b) Repeat part (a), using the assumption of unequal variances with Welch's…
A special bumper was installed on selected vehicles in a large fleet. The dollar cost of body repairs was recorded for all vehicles that were involved in accidents over a 1-year period. Those with the special bumper are the test group and the other vehicles are the control group, shown below. Each "repair incident" is defined as an invoice (which might include more than one separate type of damage). Statistic Test Group Control Group Mean Damage x¯1x¯1 = $ 1,101 x¯2x¯2 = $ 1,766 Sample Standard Deviation s1 = $ 696 s2 = $ 838 Repair Incidents n1 = 12 n2 = 9 (a) Construct a 90 percent confidence interval for the true difference of the means assuming equal variances. (Round answers to 3 decimal places. Negative values should be indicated by a minus sign.) (b) Repeat part (a), using the assumption of unequal variances with Welch's formula for d.f. (Round answers to 2 decimal places. Negative values should be indicated by a minus sign.) (d) Construct separate…
Time for pizza delivery by a certain restaurant follows a uniform distribution and can range from 20 to 45 minutes. 60% of the time, the delivery time will fall above what value?
Assume you are a psychologist studying the relationship between chocolate consumption and happiness. You ask 10 participants to rate how much chocolate (in ounces) they ate in the last week, and how happy they felt throughout the week on the average, on a scale ranging from 1 (extremely unhappy) to 10 (extremely happy). You hypothesize that there is some relationship between chocolate consumption and happiness. Here are their scores: Participant # Chocolate eaten during week (oz) Happiness rating 1 5 3 2 6 9 3 3 7 4 7 6 5 4 4 6 6 8 7 10 1 8 6 7 9 2 1 10 1 4 Is this a one-tailed or two-tailed test? Group of answer choices two-tailed one-tailed
Total plasma volume by the overall health and physical activity of an individual. Suppose that a random sample of 40 male firefighters are tested and that they have a plasma volume sample mean of x = 37.5 ml/kg (milliliters plasma per kilogram body weight). Assume that o = 7.10 ml/kg for the distribution of blood plasma. is important in determining the required plasma component in blood replacement therapy for a person undergoing surgery. Plasma volume is influenced When finding an 99% confidence interval, what is the critical value for confidence level? (Give your answer to two decimal places.) z. = (a) Find a 99% confidence interval for the population mean blood plasma volume in male firefighters. What is the margin of error? (Round your answers to two decimal places.) lower limit upper limit margin of error (b) What conditions are necessary for your calculations? (Select all that apply.) n is large the distribution of volumes is normal o is unknown the distribution of volumes is…
Hello. I appreciate any help. Thanks.
Determine the test score of John in Statistics if he has a z-score of 1.9. (SD = 4, mean = 85)
A market researcher wanted to evaluate the difference in credit charges for customers of Bracy’s. She randomly selected 100 customers and recorded their credit charges in December 2004 and January 2005. Is there evidence to show a difference in credit charges between the two months?Step 1: Step 2: α =Ho: H1:Step 3 Step 4 Step 5 Step 6 Difference: Dec. 2004 - Jan. 2005 Sample Diff: 280.74152 Std. Err: 99.50361 p-value: 0.0058
When creating a 99% CI based on data from one sample the size of n=31, which t value should be used?
myopenmath.com/assess2/?cid=208543&aid=14753792#/skip/5 HCS Bookmarks One TOS Score: 3.8/16 4/10 answered Question 5 You recently sent out a survey to determine if the percentage of adults who use social media has changed from 64%, which was the percentage of adults who used social media five years ago. Of the 2813 people who responded to survey, 1687 stated that they currently use social media. a) Use the data from this survey to construct a 94% confidence interval estimate of the proportion of adults who use social media. Record the result below in the form of (#,#). Round your final answer to four decimal places. b) Can you conclude that the percentage of adults who use social media has changed? Explain. Yes, because the proportion of adults who used social media five years ago is inside of the confidence interval. Yes, because the proportion of adults who used social media five years ago is not inside the confidence interval. No, because the proportion of adults who used social…