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In a survey on supernatural experiences, 728 of 4,003 adult Americans surveyed reported that they had seen a ghost. Assume that this sample is representative of the population of adult Americans. (a) Use the given information to estimate the proportion of adult Americans who would say they have seen a ghost. (Round your answer to three decimal places.) (b) Verify that the conditions for use of the margin of error formula to be appropriate are met. The condition that the sample is a random sample from the population of interest or the sample is selected in a way that should result in a representative sample is -Select-- v. The condition that the sample size is large is -Select-v. (c) Calculate the margin of error. (Round your answer to three decimal places.) (d) Interpret the margin of error in context. O t is unlikely that the estimated proportion of all adult Americans who would say they have seen a ghost differs from the true population proportion by less than the value calculated above. O It is likely that the estimated proportion of all adult Americans who would say they have seen a ghost differs from the true population proportion by the value calculated above. O t is impossible that the estimated proportion of all adult Americans who would say they have seen a ghost differs from the true population proportion by more than the value calculated above. O t is unlikely that the estimated proportion of all adult Americans who would say they have seen a ghost differs from the true population proportion by more than the value calculated above. O t is impossible that the estimated proportion of all adult Americans who would say they have seen a ghost differs from the true population proportion by less than the value calculated above. (e) Construct a 90% confidence interval for the proportion of all adult Americans who would say they have seen a ghost. (Use a table or SALT. Round your answers to three decimal places.) Interpret the interval. O There is a 90% chance that the true proportion of all adult Americans who would say they have seen a ghost falls directly in the middle of this interval. hest felle itbie the

In a survey on supernatural experiences, 728 of 4,003 adult Americans surveyed reported that they had seen a ghost. Assume that this sample is representative of the population of adult Americans. (a) Use the given information to estimate the proportion of adult Americans who would say they have seen a ghost. (Round your answer to three decimal places.) (b) Verify that the conditions for use of the margin of error formula to be appropriate are met. The condition that the sample is a random sample from the population of interest or the sample is selected in a way that should result in a representative sample is -Select-- v. The condition that the sample size is large is -Select-v. (c) Calculate the margin of error. (Round your answer to three decimal places.) (d) Interpret the margin of error in context. O t is unlikely that the estimated proportion of all adult Americans who would say they have seen a ghost differs from the true population proportion by less than the value calculated above. O It is likely that the estimated proportion of all adult Americans who would say they have seen a ghost differs from the true population proportion by the value calculated above. O t is impossible that the estimated proportion of all adult Americans who would say they have seen a ghost differs from the true population proportion by more than the value calculated above. O t is unlikely that the estimated proportion of all adult Americans who would say they have seen a ghost differs from the true population proportion by more than the value calculated above. O t is impossible that the estimated proportion of all adult Americans who would say they have seen a ghost differs from the true population proportion by less than the value calculated above. (e) Construct a 90% confidence interval for the proportion of all adult Americans who would say they have seen a ghost. (Use a table or SALT. Round your answers to three decimal places.) Interpret the interval. O There is a 90% chance that the true proportion of all adult Americans who would say they have seen a ghost falls directly in the middle of this interval. hest felle itbie the

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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1. DETAILS PECKSTAT2COREQ 9.R.084.S. MY NOTES In a survey on supernatural experiences, 728 of 4,003 adult Americans surveyed reported that they had seen a ghost. Assume that this sample is representative of the population of adult Americans. (a) Use the given information to estimate the proportion of adult Americans who would say they have seen a ghost. (Round your answer to three decimal places.) (b) Verify that the conditions for use of the margin of error formula to be appropriate are met. Select---v. The condition that the The condition that the sample is a random sample from the population of interest or the sample is selected in a way that should result in a representative sample is sample size is large is ---Select--- v. (c) Calculate the margin of error. (Round your answer to three decimal places.) (d) Interpret the margin of error in context. O It is unlikely that the estimated proportion of all adult Americans who would say they have seen a ghost differs from the true population proportion by less than the value calculated above. O It is likely that the estimated proportion of all adult Americans who would say they have seen a ghost differs from the true population proportion by the value calculated above. O It is impossible that the estimated proportion of all adult Americans who would say they have seen a ghost differs from the true population proportion by more than the value calculated above. O It is unlikely that the estimated proportion of all adult Americans who would say they have seen a ghost differs from the true population proportion by more than the value calculated above. O It is impossible that the estimated proportion of all adult Americans who would say they have seen a ghost differs from the true population proportion by less than the value calculated above. (e) Construct a 90% confidence interval for the proportion of all adult Americans who would say they have seen a ghost. (Use a table or SALT. Round your answers to three decimal places.) Interpret the interval. O There is a 90% chance that the true proportion of all adult Americans who would say they have seen a ghost falls directly in the middle of this interval. O we are 90% confident that the true proportion of all adult Americans who would say they have seen a ghost falls within this interval. 8:04 PM P Type here to search A D d) W 26 12/11/2020
Transcribed Image Text:1. DETAILS PECKSTAT2COREQ 9.R.084.S. MY NOTES In a survey on supernatural experiences, 728 of 4,003 adult Americans surveyed reported that they had seen a ghost. Assume that this sample is representative of the population of adult Americans. (a) Use the given information to estimate the proportion of adult Americans who would say they have seen a ghost. (Round your answer to three decimal places.) (b) Verify that the conditions for use of the margin of error formula to be appropriate are met. Select---v. The condition that the The condition that the sample is a random sample from the population of interest or the sample is selected in a way that should result in a representative sample is sample size is large is ---Select--- v. (c) Calculate the margin of error. (Round your answer to three decimal places.) (d) Interpret the margin of error in context. O It is unlikely that the estimated proportion of all adult Americans who would say they have seen a ghost differs from the true population proportion by less than the value calculated above. O It is likely that the estimated proportion of all adult Americans who would say they have seen a ghost differs from the true population proportion by the value calculated above. O It is impossible that the estimated proportion of all adult Americans who would say they have seen a ghost differs from the true population proportion by more than the value calculated above. O It is unlikely that the estimated proportion of all adult Americans who would say they have seen a ghost differs from the true population proportion by more than the value calculated above. O It is impossible that the estimated proportion of all adult Americans who would say they have seen a ghost differs from the true population proportion by less than the value calculated above. (e) Construct a 90% confidence interval for the proportion of all adult Americans who would say they have seen a ghost. (Use a table or SALT. Round your answers to three decimal places.) Interpret the interval. O There is a 90% chance that the true proportion of all adult Americans who would say they have seen a ghost falls directly in the middle of this interval. O we are 90% confident that the true proportion of all adult Americans who would say they have seen a ghost falls within this interval. 8:04 PM P Type here to search A D d) W 26 12/11/2020
i webassign.net/web/Student/Assignment-Responses/last?dep=25472606 O It is unlikely that the estimated proportion of all adult Americans who would say they have seen a ghost differs from the true population proportion by more than the value calculated above. O It is impossible that the estimated proportion of all adult Americans who would say they have seen a ghost differs from the true population proportion by less than the value calculated above. (e) Construct a 90% confidence interval for the proportion of all adult Americans who would say they have seen a ghost. (Use a table or SALT. Round your answers to three decimal places.) Interpret the interval. O There is a 90% chance that the true proportion of all adult Americans who would say they have seen a ghost falls directly in the middle of this interval. O we are 90% confident that the true proportion of all adult Americans who would say they have seen a ghost falls within this interval. O There is a 90% chance that the true proportion of all adult Americans who would say they have seen a ghost falls within this interval. O We are 90% confident that the true proportion of all adult Americans who would say they have seen a ghost falls directly in the middle of this interval. O We are 90% confident that the mean number of all adult Americans who would say they have seen a ghost falls within this interval. (f) Would a 99% confidence interval be narrower or wider than the interval calculated in part (e)? O narrower O wider Justify your answer. The z critical value for higher confidence is -Select- v resulting in a -Select- v confidence interval. Submit Answer Question 1 of 13 View Next Question Home My Assignments 8:05 PM P Type here to search O 4) G 26 12/11/2020
Transcribed Image Text:i webassign.net/web/Student/Assignment-Responses/last?dep=25472606 O It is unlikely that the estimated proportion of all adult Americans who would say they have seen a ghost differs from the true population proportion by more than the value calculated above. O It is impossible that the estimated proportion of all adult Americans who would say they have seen a ghost differs from the true population proportion by less than the value calculated above. (e) Construct a 90% confidence interval for the proportion of all adult Americans who would say they have seen a ghost. (Use a table or SALT. Round your answers to three decimal places.) Interpret the interval. O There is a 90% chance that the true proportion of all adult Americans who would say they have seen a ghost falls directly in the middle of this interval. O we are 90% confident that the true proportion of all adult Americans who would say they have seen a ghost falls within this interval. O There is a 90% chance that the true proportion of all adult Americans who would say they have seen a ghost falls within this interval. O We are 90% confident that the true proportion of all adult Americans who would say they have seen a ghost falls directly in the middle of this interval. O We are 90% confident that the mean number of all adult Americans who would say they have seen a ghost falls within this interval. (f) Would a 99% confidence interval be narrower or wider than the interval calculated in part (e)? O narrower O wider Justify your answer. The z critical value for higher confidence is -Select- v resulting in a -Select- v confidence interval. Submit Answer Question 1 of 13 View Next Question Home My Assignments 8:05 PM P Type here to search O 4) G 26 12/11/2020
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