Which of the following is the obtained chi-squared statistic for this test?
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A professor believes that, in recent years, the ethnic composition of the students in the university has changed. According to the data collected a few years ago, there were 70% of students from European origins, 20% Asian origins, 5% Indigenous, and 5% Others. To test his belief, he randomly sampled 500 students and recorded their ethnicity as shown below:
| European | 318 |
|---|---|
| Asian | 132 |
| Indigenous | 25 |
| Others | 25 |
The professor conducted a chi-squared goodness-of-fit test. Which of the following is the obtained chi-squared statistic for this test?
5.1443
8.7898
0.2288
13.1657
10.9777
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- In a simple study about coffee habit in two towns, the following information was received: Town A: Females were 40%; Total coffee drinkers were 45% and male non-coffee drinkers were 20%. Town B: Males were 55%, male non-coffee drinkers were 30% and female coffee drinkers were 15%. Represent the above data in a tabular form.To compare two elementary schools regarding teaching of reading skills, 12 sets of identical twins were used. In each case, one child was selected at random and sent to school A, and his or her twin was sent to school B. Near the end of fifth grade, an achievement test was given to each child. The results follow: Twin Pair 1 2 3 4 5 6 School A 80 145 118 90 112 118 School B 83 135 115 105 105 113 Twin Pair 7 8 9 10 11 12 School A 98 112 115 144 124 96 School B 93 87 98 132 135 105 Suppose a sign test for matched pairs with a 5% level of significance is used to test the hypothesis that the schools have the same effectiveness in teaching reading skills against the alternate hypothesis that the schools have different levels of effectiveness in teaching reading skills. Let p denote portion of positive signs when the scores of school B are subtracted from the corresponding scores of school A.…Kindly assist with creating bar charts, or pie charts for the below results; The results of this study were based on interviews issued and completed by eleven (11) employees at the Hotel. This research study comprised 31.4% of the total workforce across the three departments, with a total of 35 employees who varied in age from 16 years to above 65 years. 63.6% of individuals who participated were female, while 36% were male. The interviews included participation from 30% of employees in the housekeeping department, 33% from Guest Services, and 31% from the Food and Beverage department. There is a higher representation of females across all departments, with a total of 7 females compared to 4 males. There is a range of tenure lengths, with some employees having just started (1 year) and others having been with the hotel for longer periods (up to 14.5 years).
- The testing data set (inputs: A, B, and C, output: Class) is given together with testing results of the classification (predicted output). Find and plot two points on the ROC curve for the threshold values of 0.5 and 0.8. A 10 20 30 40 15 B 2 1 3 2 1 C A B A B B Class (Output) 1 0 1 1 0 Predicted Output 0.97 0.61 0.77 0.91 0.12A sample of 296 students at a university is surveyed. The students are classified according to gender ("female" or "male"). They are also classified according to major ("biology", "business", "engineering", "mathematics", or "computer science"). The results are given in the contingency table below. Biology Business Engineering Mathematics Female 33 30 22 45 Male 24 43 26 16 Among all the students in the sample, what is the relative frequency of male computer science majors? Round your answer to two decimal places. 1 X Computer science 41 16 Españ AaA television station wishes to study the relationship between viewership of its 11 p.m. news program and viewer age (18 years or less, 19 to 35, 36 to 54, 55 or older). A sample of 250 television viewers in each age group is randomly selected, and the number who watch the station’s 11 p.m. news is found for each sample. The results are given in the table below. Age Group Watch11 p.m. News? 18 or less 19 to 35 36 to 54 55 or Older Total Yes 37 46 59 83 225 No 213 204 191 167 775 Total 250 250 250 250 1,000 (a) Let p1, p2, p3, and p4 be the proportions of all viewers in each age group who watch the station’s 11 p.m. news. If these proportions are equal, then whether a viewer watches the station’s 11 p.m. news is independent of the viewer’s age group. Therefore, we can test the null hypothesis H0 that p1, p2, p3, and p4 are equal by carrying out a chi-square test for independence. Perform this test by setting α = .05. (Round your answer to 3 decimal places.)…
- The General Social Survey is an annual survey given to a random selection of about 1500 adults in the United States. Among the many questions asked are "What is the highest level of education you've completed?" and "If you're employed full-time, how many hours do you spend working at your job during a typical week?" In a recent year, 1079 respondents answered both questions. The summary statistics are given in the chart below. (The sample data consist of the times, in hours per week, that were given by the respondents.) Sample Sample Sample size Groups mean variance Less than h.s. High school Bachelor's 258 40.9 101.8 263 41.8 97.5 270 42.2 94.4 Graduate 288 43.0 98.7 Send data to calculator Send data to Excel To decide if there are any differences in the mean hours per week worked by these different groups, we can perform a one-way, independent-samples ANOVA test. Such a test uses the following statistic. Variation between the samples F= Variation within the samples For the data from…A television station wishes to study the relationship between viewership of its 11 p.m. news program and viewer age (18 years or less, 19 to 35, 36 to 54, 55 or older). A sample of 250 television viewers in each age group is randomly selected, and the number who watch the station’s 11 p.m. news is found for each sample. The results are given in the table below. Age Group Watch11 p.m. News? 18 or less 19 to 35 36 to 54 55 or Older Total Yes 49 59 61 84 253 No 201 191 189 166 747 Total 250 250 250 250 1,000 (a) Let p1, p2, p3, and p4 be the proportions of all viewers in each age group who watch the station’s 11 p.m. news. If these proportions are equal, then whether a viewer watches the station’s 11 p.m. news is independent of the viewer’s age group. Therefore, we can test the null hypothesis H0 that p1, p2, p3, and p4 are equal by carrying out a chi-square test for independence. Perform this test by setting α = .05. (Round your answer to 3 decimal places.)…A random sample of 10 compact cars, 10 mid-size cars, and 10 luxury cars were selected. The time (in seconds) each of the randomly selected cars required to accelerate from 0 to 60 mph was looked up on the Autos.com website. The results are presented below. Car Type Time (in seconds) Required to Accelerate from 0 to 60 mph Compact 9.3 8.1 10.2 8.8 9.0 9.3 7.7 9.2 9.4 8.6 Mid-Size 6.9 5.7 8.3 7.7 8.6 5.9 6.1 8.8 6.1 7.2 Luxury 5.7 6.3 5.4 4.7 6.2 7.0 5.9 5.3 6.3 5.0 Conduct a hypothesis test using ! = 0.05 to determine whether the mean time required to accelerate from 0 to 60 mph is the same for compact, mid-size, and luxury cars. (No accounting or excel, I need help solving it.)
- Twenty-nine college students, identified as having a positive attitude about Mitt Romney as compared to Barack Obama in the 2012 presidential election, were asked to rate how trustworthy the face of Mitt Romney appeared, as represented in their mental image of Mitt Romney’s face. Ratings were on a scale of 0 to 7, with 0 being “not at all trustworthy” and 7 being “extremely trustworthy.” Here are the 29 ratings: 2.6 3.2 3.7 3.3 3.4 3.6 3.7 3.8 3.9 4.1 4.2 4.9 5.7 4.2 3.9 3.2 4.5 5.0 5.0 4.6 4.6 3.9 3.9 5.3 2.8 2.6 3.0 3.3 3.7 a 95% confidence interval for the mean rating. Is there significant evidence at the 5% level that the mean rating is greater than 3.5 (a neutral rating)?A Statistics class reports the following data on Sex and Eye Color for students in the class: Green/Hazel/Other Total Blue 8 Brown 20 34 4 16 32 36 66 Males Females Total 12 16 12 18 a. What percent of the blue-eyed students are male? type your answer... % b. What percent of the class are blue-eyed males? % type your answer... c. What percent of the male students have blue eyes? type your answer... % d. What percent of the students who do not have blue eyes are females? % type your answer... e. What's the conditional distribution of sex for the brown-eyed students? Male: type your answer... % Female: type your answer... % f. What's the conditional distribution of Eye Color for the males? Blue: type your answer... Brown: type your answer... % %Below are the numbers of patients classified as underweight, normal weight, overweight and obese according to their diabetes status. If a patient is selected at random: What proportion of normal weight patients are not diabetic? What proportion of patients are normal weight or underweight? Underweight Normal Weight Overweight Obese Row Totals Diabetic 8 34 65 43 150 Not Diabetic 12 85 93 40 230 Column Totals 20 119 158 83 380
