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An unsymmetrical flexural member consists of a ½ x 12 top flange, a ½ x 7 bottom flange, and a 3/8 x 16 web. b.) If A572 Grade 50 is used, what is the plastic moment Mp for the horizontal plastic neutral axis (already answered) QUESTION: SHOW THE SOLUTION FOR GETTING THE y for the top and bottom flange. and draw the figure for better understandin

An unsymmetrical flexural member consists of a ½ x 12 top flange, a ½ x 7 bottom flange, and a 3/8 x 16 web. b.) If A572 Grade 50 is used, what is the plastic moment Mp for the horizontal plastic neutral axis (already answered) QUESTION: SHOW THE SOLUTION FOR GETTING THE y for the top and bottom flange. and draw the figure for better understandin

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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An unsymmetrical flexural member consists of a ½ x 12 top flange, a ½ x 7 bottom flange, and a 3/8 x 16 web.

b.) If A572 Grade 50 is used, what is the plastic moment Mp for the horizontal plastic neutral axis (already answered)

QUESTION: SHOW THE SOLUTION FOR GETTING THE y for the top and bottom flange. and draw the figure for better understanding

1 = ΣΑΥ 33.59 ΣΑ 7.750 For area below PNA, www.w * 4. 334 in. Component bot. fl web Sum 64.61 7.750 52 ΣΑy ΣΑ Plastic moment: Mp = Cx moment arm Tx moment arm = AF,G1 + 72) = 7.750(50)(4.334 + 8.337) A 3.500 4.250 7.750 = y 11.58 5.667 8. 337 in. wwwww = 387.5(12.67) = 4910 in-kips = 409 ft-kips Ay 40.53 24.08 64.61 My = 409 ft-kips
Transcribed Image Text:1 = ΣΑΥ 33.59 ΣΑ 7.750 For area below PNA, www.w * 4. 334 in. Component bot. fl web Sum 64.61 7.750 52 ΣΑy ΣΑ Plastic moment: Mp = Cx moment arm Tx moment arm = AF,G1 + 72) = 7.750(50)(4.334 + 8.337) A 3.500 4.250 7.750 = y 11.58 5.667 8. 337 in. wwwww = 387.5(12.67) = 4910 in-kips = 409 ft-kips Ay 40.53 24.08 64.61 My = 409 ft-kips
5.2-2 (a) Area above PNA = Area below PNA 12(1/2) + (-1/2)(3/8) = (1/2 +16 − ÿ)(3/8) + 7(1/2) ỹ = 5.17 in. (b) To locate centroids of areas, take moments about plastic neutral axis. For area above PNA, Component top fl web Sum A 6.000 1.750 7.750 y 4.917 2.334 y = 5.167 Ay 29.50 4.085 33.59
Transcribed Image Text:5.2-2 (a) Area above PNA = Area below PNA 12(1/2) + (-1/2)(3/8) = (1/2 +16 − ÿ)(3/8) + 7(1/2) ỹ = 5.17 in. (b) To locate centroids of areas, take moments about plastic neutral axis. For area above PNA, Component top fl web Sum A 6.000 1.750 7.750 y 4.917 2.334 y = 5.167 Ay 29.50 4.085 33.59
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Not the ȳ. I NEED THE y for the top and bottom flange? how did they get the values 4.917 and 11.58

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